Statistics: The Art and Science of Learning from Data (4th Edition)
4th Edition
ISBN: 9780321997838
Author: Alan Agresti, Christine A. Franklin, Bernhard Klingenberg
Publisher: PEARSON
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Chapter 7, Problem 34CP
a.
To determine
Identify the
b.
To determine
Find the number of standard deviations that the sample result fall from the mean of the sampling distribution.
c.
To determine
Explain the reason that obtaining 3 out of 12 shots will not be surprising.
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The height of bedridden patients is often estimated from the length of the patient's ulna, the distance between the point on the elbow
and the prominent bone on the wrist. Eight men over the age of 65 had both their height (in centimeters) and the length of their ulna
(in centimeters) measured. The data are given in the table below.
Ulna length (cm)
20
23
24
26
27
29
30
31
Height (cm)
160
163
166
168
171
178
182
186
Let x denote a patient's ulna length (in cm) and y denote the patient's height (in cm). Assume that the population distributions for both
ulna length and height are approximately normal. The following summary measures were obtained from the data.
X = 26.25, ỹ = 171.75, SSxx = 99.5, SSyy= 609.5, SSxy= 238.5
ху
We wish to find the least squares regression line for the data in this table using ulna length as an independent variable and height as a
dependent variable.
Use the information to estimate the slope of the least squares regression line. Enter your answer using three…
Chapter 7 Solutions
Statistics: The Art and Science of Learning from Data (4th Edition)
Ch. 7.1 - Simulating the exit poll Simulate an exit poll of...Ch. 7.1 - Simulate condo solicitations A company that is...Ch. 7.1 - Condo sample distribution Consider the sampling...Ch. 7.1 - iPhone apps Let p = 0.25 be the proportion of...Ch. 7.1 - Other scenario for exit poll Refer to Examples 1...Ch. 7.1 - Prob. 6PBCh. 7.1 - Random variability in baseball A baseball player...Ch. 7.1 - Relative frequency of heads Construct the sampling...Ch. 7.1 - Prob. 9PBCh. 7.1 - Effect of n on sample proportion The figure...
Ch. 7.1 - Syracuse full-time students Youd like to estimate...Ch. 7.1 - Gender distributions At a university, 60% of the...Ch. 7.1 - Prob. 13PBCh. 7.1 - Prob. 14PBCh. 7.2 - Simulate taking midterms Assume that the...Ch. 7.2 - Education of the self-employed According to a...Ch. 7.2 - Rolling one die Let X denote the outcome of...Ch. 7.2 - Playing roulette A roulette wheel in Las Vegas has...Ch. 7.2 - Simulate rolling dice Access the Sampling...Ch. 7.2 - Prob. 20PBCh. 7.2 - Shared family phone plan A recent personalized...Ch. 7.2 - Dropped from plan previous exercise mentions that...Ch. 7.2 - Restaurant profit? Jans All You Can Eat Restaurant...Ch. 7.2 - Survey accuracy A study investigating the...Ch. 7.2 - Blood pressure Vincenzo Baranello was diagnosed...Ch. 7.2 - Household size According to the 2010 U.S. census...Ch. 7.2 - Average monthly sales A large corporation employs...Ch. 7.2 - Prob. 28PBCh. 7.2 - CLT for skewed population Access the Sampling...Ch. 7.2 - Prob. 30PBCh. 7 - Practicing the Basics Exam performance An exam...Ch. 7 - Blue eyes According to a Boston Globe story, only...Ch. 7 - Prob. 33CPCh. 7 - Prob. 34CPCh. 7 - Prob. 35CPCh. 7 - Returning shipment Refer to the previous exercise,...Ch. 7 - Prob. 37CPCh. 7 - Home runs Based on data from the 2010 Major League...Ch. 7 - Physicians assistants The 2006 AAPA survey of the...Ch. 7 - Bank machine withdrawals An executive in an...Ch. 7 - PDI The scores on the Psychomotor Development...Ch. 7 - Number of sex partners According to recent General...Ch. 7 - Prob. 43CPCh. 7 - Too little or too much cola? Refer to the previous...Ch. 7 - Prob. 45CPCh. 7 - Prob. 46CPCh. 7 - Prob. 47CPCh. 7 - Purpose of sampling distribution Youd like to...Ch. 7 - Prob. 49CPCh. 7 - Prob. 50CPCh. 7 - Prob. 51CPCh. 7 - Prob. 52CPCh. 7 - Prob. 53CPCh. 7 - Winning at roulette Part b of Example 7 used the...Ch. 7 - True or false As the sample size increases, the...Ch. 7 - Prob. 56CPCh. 7 - Prob. 57CPCh. 7 - Prob. 58CPCh. 7 - Prob. 59CPCh. 7 - Prob. 60CPCh. 7 - Prob. 61CPCh. 7 - Prob. 62CPCh. 7 - Prob. 63CP
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- Read the decimal-inch measurement on the vernier height gage in Figure 41-2.arrow_forwardThe height of bedridden patients is often estimated from the length of the patient's ulna, the distance between the point on the elbow and the prominent bone on the wrist. Eight men over the age of 65 had both their height (in centimeters) and the length of their ulna (in centimeters) measured. The data are given in the table below. Ulna length (cm) 20 23 24 26 27 29 30 31 Height (cm) 160 163 166 168 171 178 182 186 Let x denote a patient's ulna length (in cm) and y denote the patient's height (in cm). Assume that the population distributions for both ulna length and height are approximately normal. The following summary measures were obtained from the data. X = 26.25, ỹ = 171.75, SSxx = 99.5, SSyy= 609.5, SSxy= 238.5 ху We wish to find the least squares regression line for the data in this table using ulna length as an independent variable and height as a dependent variable. Estimate the y-intercept of the least squares regression line. Enter your answer using three decimal places.arrow_forwardThe ratio of dogs to cats in the neighborhood was 2 to 5. If there were 10 dogs, predict how many cats were there. 0 17 cats O 7 cats O 20 cats 25 catsarrow_forward
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