(a) Interpretation: The number of moles of Cl − ion present in the sample is to be calculated. Concept introduction: Moles of the chloride ion are equal to the moles of the silver ion added in the system in the titration of the chloride ion sample with silver nitrate. Numbers of moles are defined as the given mass of the species divided by the molar mass of that species.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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Question

Chapter 7, Problem 2ASA

Interpretation Introduction

(a)

Interpretation:

The number of moles of Cl− ion present in the sample is to be calculated.

Concept introduction:

Moles of the chloride ion are equal to the moles of the silver ion added in the system in the titration of the chloride ion sample with silver nitrate. Numbers of moles are defined as the given mass of the species divided by the molar mass of that species.

Interpretation Introduction

(b)

Interpretation:

The concentration of the chloride ion in the diluted solution is to be determined.

Concept introduction:

The concentration of the chloride ion present in the unknown sample is determined by the argentometric titration. The chloride ion sample is titrated with the silver nitrate solution to calculate the concentration of the chloride ion.

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5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3

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