Explanation Given: The provided problem is, x 1 + x 2 + x 3 ≤ 100 2 x 1 + 3 x 2 ≤ 500 x 1 + 2 x 3 ≤ 350 Formula used: Calculation: From the above information the constrains are as, x 1 + x 2 + x 3 ≤ 100 2 x 1 + 3 x 2 ≤ 500 x 1 + 2 x 3 ≤ 350 where x 1 , x 2 and x 3 are all non-negative. The first of these constraints says that x 1 + x 2 + x 3 ≤ 100 is less than or perhaps equal to 100. Suppose s 1 is the slack variable, Therefore, the first equation is, x 1 + x 2 + x 3 + s 1 = 100 The second constraints 2 x 1 + 3 x 2 ≤ 500 can be expressed by adding slack variable s 2 . Therefore, the second equation is, 2 x 1 + 3 x 2 + s 2 = 500 The third constraints x 1 + 2 x 3 ≤ 350 can be expressed by adding slack variable s 3 . Therefore, the third equation is, x 1 + 2 x 3 + s 3 = 350 The maximum profit function z = 5 x 1 + 6 x 2 + 3 x 3 . Now linear programming problem can be written as follows, The maximum profit z = 5 x 1 + 6 x 2 + 3 x 3 Subjected to: x 1 + x 2 + x 3 ≤ 100 2 x 1 + 3 x 2 ≤ 500 x 1 + 2 x 3 ≤ 350 Here, x 1 ≥ 0 , x 2 ≥ 0 , x 3 ≥ 0 , s 1 ≥ 0 , s 2 ≥ 0 , s 3 ≥ 0 Thus, the initial simplex tableau is/; x 1 x 2 x 3 s 1 s 2 s 3 [ 1 1 1 1 0 0 100 2 3 0 0 1 0 500 1 0 2 0 0 1 350 − 5 − 6 − 3 0 0 0 0 ] Locate the most negative indicator

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ISBN: 9780135904282

Author: Lial, HUNGERFO

Publisher: PEARSON

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Chapter 7, Problem 29RE

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To calculate: The maximum value of the provided linear programming problem.

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Chapter 7, Problem 28RE

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Ch. 7.1 - Checkpoint 1 Graph the given...Ch. 7.1 - Prob. 2CP Ch. 7.1 - Prob. 3CP Ch. 7.1 - Prob. 4CP Ch. 7.1 - Prob. 5CP Ch. 7.1 - Checkpoint 6 Graph the feasible region of the...Ch. 7.1 - Prob. 7CP Ch. 7.1 - Match the inequality with its graph, which is one...Ch. 7.1 - Match the inequality with its graph, which is one...Ch. 7.1 - Match the inequality with its graph, which is one...

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