Materials Science And Engineering
10th Edition
ISBN: 9781119405498
Author: Callister, William D., Jr, RETHWISCH, David G., Jr., 1940- Author.
Publisher: Wiley,
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Chapter 7, Problem 20QAP
To determine
Explain why small-angle grain boundaries are not as effective in interfering with the slip process as are high angle grain boundaries.
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A simply supported beam is subjected to the end couples (bending is about the strong axis) and the axial load shown in the figure
below. These moments and axial load are from service loads and consist of equal parts dead load and live load. Lateral support is
provided only at the ends. Neglect the weight of the beam and investigate this member as a beam-column. Use Fy
that P40 k and M = 68 ft-k.
For W10 × 33: I = 171 in.4;
10 ft and C₁ = 1.0: Mn = 134 ft-kips and Mn/₁ = 89.3 ft-kips;
=
50 ksi. Suppose
for Lb
for Lc
-
= 10 ft: Pn 330 kips and Pr/c
=
220 kips.
W10 X 33
P
M
M
10'
Pu
A)
+
Ферп 9
a. Use LRFD.
Select the interaction formula:
Mur
84, Mnz
Muy
+
<1.0
Фь Мпу
Pu
Mur
Muy
B)
+
+
≤ 1.0
20c Pn
Фь Мих
nx
ФоМпу
-Select- ✓
Compute the interaction formula.
(Express your answer to three significant figures.)
-Select- 1.0
This member is -Select-
b. Use ASD.
Select the interaction formula:
Ра
8
Max
May
A)
+
+
<1.0
Pn/c
Mnx/b Mny/b
Pa
Max
May
B)
+
+
1.0
2Pn/c Mnx/b Mny/b
-Select-
Compute the…
Correct detailed answer and complete fbd only. I will upvote.
The compound shaft, composed of steel,aluminum, and bronze segments, carries the two torquesshown in the figure. If TC = 250 lb-ft, determine the maximumshear stress developed in each material (in ksi). The moduliof rigidity for steel, aluminum, and bronze are 12 x 106 psi, 4x 106 psi, and 6 x 106 psi, respectively
Determine whether the given member satisfies the appropriate AISC interaction equation. Do not consider moment amplification. The loads are
50% dead load and 50% live load. Bending is about the x axis, and the steel is ASTM A992. Suppose that P = 280 k.
For W12 x 106 with Fy = 50 ksi and Lc = 14 feet:
Ферп 1130 kips, Pn/Sc
= 755 kips,
Mn = 597 ft-kips, Mn/₁ = 397 ft-kips.
P
240 ft-k
W12 X 106
14'
K₁ = Ky
= 1.0
240 ft-k
a. Use LRFD.
P
Determine the factored axial compressive load and the factored bending moment.
(Express your answers to three significant figures.)
P₁ =
Mu =
kips
ft-kips
Select the interaction formula:
P₁
A)
+
Мих
Muy
+
≤1.0
Ферп 9 Фь Мих
of Mny
Pu
Мих
Muy
B)
+
20c Pn
Mnz
+
<1.0
Фь Мпу
-Select-
Compute the interaction formula.
(Express your answer to three significant figures.)
-Select- 1.0
This member -Select-
b. Use ASD.
the AISC Specification.
Determine the total axial compressive load and the maximum bending moment.
(Express your answers to three significant…
Chapter 7 Solutions
Materials Science And Engineering
Ch. 7 - Prob. 1QAPCh. 7 - Prob. 2QAPCh. 7 - Prob. 3QAPCh. 7 - Prob. 4QAPCh. 7 - Prob. 5QAPCh. 7 - Prob. 7QAPCh. 7 - Prob. 8QAPCh. 7 - Prob. 9QAPCh. 7 - Prob. 10QAPCh. 7 - Prob. 11QAP
Ch. 7 - Prob. 12QAPCh. 7 - Prob. 13QAPCh. 7 - Prob. 19QAPCh. 7 - Prob. 20QAPCh. 7 - Prob. 21QAPCh. 7 - Prob. 22QAPCh. 7 - Prob. 23QAPCh. 7 - Prob. 25QAPCh. 7 - Prob. 26QAPCh. 7 - Prob. 33QAPCh. 7 - Prob. 34QAPCh. 7 - Prob. 35QAPCh. 7 - Prob. 36QAPCh. 7 - Prob. 42QAPCh. 7 - Prob. 1DPCh. 7 - Prob. 3DPCh. 7 - Prob. 4DPCh. 7 - Prob. 7DPCh. 7 - Prob. 1FEQPCh. 7 - Prob. 2FEQPCh. 7 - Prob. 3FEQP
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