
(a)
Interpretation:
The energy that speed is equal to the
(b)
Interpretation:
The number of wave cycles passing a stationary point in one second.
(c)
Interpretation:
The energy that is required to remove a valence electron from an isolated gaseous atom.
(d)
Interpretation:
The rule which states that electrons are arranged in atomic orbitals in such a manner that the electrons that have the same energy are majorly arranged as unpaired.
(e)
Interpretation:
The description of the arrangement of electrons in an atomic sublevel.
(f)
Interpretation:
The electron is present the inner side of an atom and is not considered as a valence electron.
(g)
Interpretation:
A region in space where the probability of finding an electron is maximum.
(h)
Interpretation:
A spectrum that consists of all wavelengths of the visible light.
(i)
Interpretation:
The species that have the same number of electrons.

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Chapter 7 Solutions
Introduction To Chemistry 5th Edition
- Draw the most stable chair conformation of 1-ethyl-1-methylcyclohexane, clearly showing the axial and equatorial substituents. [4] Draw structures corresponding to the following IUPAC name for each of the following compounds; [5] i) 4-Isopropyl-2,4,5-trimethylheptane ii) trans-1-tert-butyl-4-ethylcyclohexane iii) Cyclobutylcycloheptane iv) cis-1,4-di-isopropylcyclohexane (chair conformation) v) 3-Ethyl-5-isobutylnonanearrow_forwardDraw and name molecules that meet the following descriptions; [4] a) An organic molecule containing 2 sp2 hybridised carbon and 1 sp-hybridised carbon atom. b) A cycloalkene, C7H12, with a tetrasubstituted double bond. Also answer question 2 from the imagearrow_forwardH 14. Draw the line angle form of the following molecule make sure you use the proper notation to indicate spatial positioning of atoms. F F H 15. Convert the following condensed form to line angle form: (CH3)3CCH2COCH2CON(CH2CH3)2arrow_forward
- In a reaction between two reactants A and B, the half-life is the same for both only if(A) the stoichiometry A:B is 1:1.(B) the stoichiometry A:B is 1:2 or 2:1.arrow_forwardIn a reaction between two reactants A and B, the half-life is the same for both.(1) Only if the stoichiometry A:B is 1:1.(2) If the initial quantities of A and B are in their stoichiometric ratios.arrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Calculate the measurement of uncertainty and provide the data in a spreadsheet table. Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32 152.87 151.24 153.26 152.02 152.90 152.87 151.49 152.46 152.58arrow_forward
- 1. Predict the organic product(s) of the following reactions. Assume excess of reagents unless otherwise noted. a) &l BH3 •THF b) 1) NaOH 2) H3O+ solve d) ala 1) EtMgBr 2) H3O+ e) H2N سكر CuLi NH2 1) SOCI2 2) EtMgBr 3) H3O+ NC H3O+ Δarrow_forwardThere are 48 pairs of students in the following table. Each pair has quantitatively determined the mass of taurine in a 250 mL can of the popular energy drink marketed as “Munster” using High Performance Liquid Chromatography (HPLC). The class results are presented below: QUESTION: Summarise and report these results including an indication of measurement uncertainty. In both calculation samples calculate if an outlier is present, max value, number of samples, mean, standard deviation, g (suspect), g (critical) and t (critical). Mass of Taurine (mg) Mass of Taurine (mg) (Table continued) 152.01 152.23 151.87 151.45 154.11 152.64 152.98 153.24 152.88 151.45 153.49 152.48 150.68 152.33 151.52 153.63 152.48 151.68 153.17 153.40 153.77 153.67 152.34 153.16 152.57 153.02 152.86 151.50 151.23 152.57 152.72 151.54 146.47 152.38 152.44 152.54 152.53 152.54 151.32…arrow_forwardIndicate the rate expressions for reactions that have order 0, 1, and 2.arrow_forward
- PROBLEMS Q1) Label the following salts as either acidic, basic, or neutral a) Fe(NOx) c) AlBr b) NH.CH COO d) HCOON (1/2 mark each) e) Fes f) NaBr Q2) What is the pH of a 0.0750 M solution of sulphuric acid?arrow_forward8. Draw all the resonance forms for each of the fling molecules or ions, and indicate the major contributor in each case, or if they are equivalent (45) (2) -PH2 سمة مدarrow_forwardA J то گای ه +0 Also calculate the amount of starting materials chlorobenzaldehyde and p-chloroacetophenone required to prepare 400 mg of the given chalcone product 1, 3-bis(4-chlorophenyl)prop-2-en-1-one molar mass ok 1,3-bis(4-Chlorophenyl) prop-2-en-1-one = 277.1591m01 number of moles= 0.400/277.15 = 0.00144 moles 2 x 0.00 144=0.00288 moves arams of acetophenone = 0.00144 X 120.16 = 0.1739 0.1739x2=0.3469 grams of benzaldehyde = 0.00144X106.12=0.1539 0.1539x2 = 0.3069 Starting materials: 0.3469 Ox acetophenone, 0.3069 of benzaldehyde 3arrow_forward
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