The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L. Introduction: Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C n (H 2 O) n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Show a mechanism that leads to the opening of the ring below under acid-catalyzed conditions. Give the correct Fischer projection for this sugar.

What is the stereochemical relationship between B & C?

Don't use ai or any chat gpt will dislike okk just use accurate information okkk okkk just solve full accurate. don't use guidelines okk just did it accurate 100% sure experts solve it correct complete solutions okkk follow all instructions requirements okkk

Answer 2

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 6

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 7

Chapter 7, Problem 1P

Summary Introduction

To explain: The reason behind the sugar alcohol (monosaccharide derivatives) is no longer designated as D or L.

Introduction:

Monosaccharide having five carbons is known as pentose. The molecular formula of carbohydrate is C_n(H₂O)_n where n represents a whole number like 3 or higher. Monosaccharide contains various functional groups like alcohol, aldehyde or ketone groups.

Answer 8

Expert Solution & Answer

Answer to Problem 1P

Answer: Fig.1 represents the structure of glyceraldehyde.

Pictorial representation: Fig.1 represents the structure of glyceraldehyde.

SaplingPlus for Lehninger Principles of Biochemistry (Six-Month Access), Chapter 7, Problem 1P

Fig.1: Structure of glyceraldehyde.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

Explanation:

Glyceraldehyde belongs to a group of monosaccharide and chemical formula for glyceraldehyde is C₃H₆O₃. The carbonyl group present at 1^st position of glyceraldehyde gets reduced into hydroxyl group. This reduction of carbonyl group results in the formation of glycerol structure. Fig.1 represents the structure of glyceraldehyde.

If the central carbon atom of a compound is bonded with four different functional groups, then the compound is said to be non-super imposable. On the basis of the arrangement of H and OH group present in chiral carbon atom, the compound is designated as D or L forms. L-form of glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the left side of the molecule. In D-form, glyceraldehyde has the -OH groups at the chiral center present far from carbonyl on the right side of the molecule. In glycerol, there is no chiral carbon is present. Thus, the sugar alcohol is no longer designated as D or L-form.

Answer 12

Ch. 7 - Prob. 1P Ch. 7 - Prob. 2P Ch. 7 - Prob. 3P Ch. 7 - Prob. 4P Ch. 7 - Prob. 5P Ch. 7 - Prob. 6P Ch. 7 - Prob. 7P Ch. 7 - Prob. 8P Ch. 7 - Prob. 9P Ch. 7 - Prob. 10P

Concept explainers

Videos

Answer to Problem 1P

Explanation of Solution

Want to see more full solutions like this?

Chapter 7 Solutions