Calculate the mean and standard deviation of violent television program viewers.

Question

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Answer 1

Question

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

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Answer 2

Question

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

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Answer 3

Question

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

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Answer 4

Question

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

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Answer 5

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

Answer 6

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

Answer 7

Chapter 7, Problem 164CE

(a)

To determine

Calculate the mean and standard deviation of violent television program viewers.

Answer 8

(a)

Expert Solution

Explanation of Solution

The probability distribution of the number of viewers of violent and non-violent television program shows is shown below:

Table 1

Viewers of violent shows
X	0	1	2	3	4	5
P(X)	0.36	0.22	0.20	0.09	0.08	0.05
Viewers of nonviolent shows
X	0	1	2	3	4	5
P(X)	0.15	0.18	0.23	0.26	0.10	0.08

The mean of number of correct answers among viewers of violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.36) + 1(0.22) + 2(0.20) + 3(0.09) + 4(0.08)+5(0.05))=1.46

The mean value is 1.46.

The standard deviation (square root of variance) of the number of correct answers among viewers of violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−1.46)2(0.36)+(1−1.46)2(0.22)+(2−1.46)2(0.20)+(3−1.46)2(0.09)+(4−1.46)2(0.08)+(5−1.46)2(0.05)}=2.23σ=σ2= 2.23=1.49

The standard deviation is 1.49.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Economics Concept Introduction

Probability distribution: Probability distribution shows the probabilities of incidence of different likely outcomes in a test.

Answer 13

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45

The standard deviation is 1.45.

Answer 14

(b)

To determine

Calculate the mean and standard deviation of non-violent television program viewers.

Answer 15

(b)

Expert Solution

Explanation of Solution

The mean of number of correct answers among viewers of non-violent television programs is calculated as follows:

μ=E(X)=∑xP(x)=(0(0.15) + 1(0.18) + 2(0.23) + 3(0.26) + 4(0.10)+5(0.08))=2.22

The mean value is 2.22.

The standard deviation (square root of variance) of the number of correct answers among viewers of non-violent television programs is calculated as follows:

σ2=V(X)=∑(x-μ)2P(x)={(0−2.22)2(0.15)+(1−2.22)2(0.18)+(2−2.22)2(0.23)+(3−2.22)2(0.26)+(4−2.22)2(0.10)+(5−2.22)2(0.08)}=2.11σ=σ2= 2.11=1.45