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Concept explainers
(a)
Interpretation:
The formula of the polyatomic ion needs to be determinedhaving similar Lewis structure as the
Concept introduction:
The Lewis structures are used to write a shorthand configuration of number of available valence electrons in an atom for bonding. This structure deals with the magic number 8 and hence the octet completion is shown by the bonded electrons between the atoms.
This structure is made on basis of octet rule understanding and it is made sure that the number of electrons surrounding an atom must not divert from the octet.
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Answer to Problem 15QAP
Explanation of Solution
Given Information:
The molecule is Cl2.
Here thetotal valence electrons are:
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
A similar type of Lewis structure is possible in only such polyatomic ion which has nearly matching electronegativities and same number of valence electrons.
In this pattern, the hypochlorite anion
Here, the valence electrons are:
The bond pair electrons are the number of electrons used in bond formation.
Looking at the structure,
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
The Lewis structure will be drawn as:
(b)
Interpretation:
The formula of the polyatomic ion needs to be determined having similar Lewis structure as the
Concept introduction:
The Lewis structures are used to write a shorthand configuration of number of available valence electrons in an atom for bonding. This structure deals with the magic number 8 and hence the octet completion is shown by the bonded electrons between the atoms.
This structure is made on basis of octet rule understanding and it is made sure that the number of electrons surrounding an atom must not divert from the octet.
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Answer to Problem 15QAP
Explanation of Solution
Given Information:
The molecule is H2 SO4.
Here the total valence electrons are:
Looking at the structure,
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
Now, in this pattern, the anion
Here the valence electrons are:
Looking at the structure,
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
The Lewis structure will be drawn as:
(c)
Interpretation:
The formula of the polyatomic ion needs to be determined having similar Lewis structure as the
Concept introduction:
The Lewis structures are used to write a shorthand configuration of number of available valence electrons in an atom for bonding. This structure deals with the magic number 8 and hence the octet completion is shown by the bonded electrons between the atoms.
This structure is made on basis of octet rule understanding and it is made sure that the number of electrons surrounding an atom must not divert from the octet.

Answer to Problem 15QAP
Explanation of Solution
Given Information:
The molecule is CH4.
Here the total valence electrons are:
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
A similar type of Lewis structure is possible in only such polyatomic ion, which has nearly matching electronegativities and same number of valence electrons.
In this pattern, the ammonium ion
Here, the valence electrons are:
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
The Lewis structure will be drawn as:
(d)
Interpretation:
The formula of the polyatomic ion needs to be determined having similar Lewis structure as the
Concept introduction:
The Lewis structures are used to write a shorthand configuration of number of available valence electrons in an atom for bonding. This structure deals with the magic number 8 and hence the octet completion is shown by the bonded electrons between the atoms.
This structure is made on basis of octet rule understanding and it is made sure that the number of electrons surrounding an atom must not divert from the octet.

Answer to Problem 15QAP
Explanation of Solution
Given Information:
The molecule is GeCl4.
Here the total valence electrons are:
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
A similar type of Lewis structure is possible in only such polyatomic ion, which has nearly matching electro negativities and same number of valance electrons.
In this pattern, the ion
Here, the valence electrons are:
Bond pair electrons are obtained as:
Similarly, lone pairs are counted as:
The Lewis structure will be drawn as:
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Chapter 7 Solutions
OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)
- Question 3 What best describes the product of the following reaction? 1. CH3CH2MgBr (2 eq) 2. H a new stereocenter will not be formed a new stereocenter will be formed an alkyl halide will result an alkane will result an aromatic compound will result 1 ptsarrow_forwardRank the following from most to least reactive toward nucleophilic attack. 1. [Select] [Select] 2. Acyl halide Aldehyde 3. Carboxylate ion 4. Carboxylic acid Ketone 5. [Select]arrow_forwardQuestion 10 1 pts Which of the following is the most accurate nomenclature? 1-hydroxy-1-methyldecane-4,7-dione 2-hydroxy-2-methyldecane-5,8-dione 4,6-dioxo-2-methyldecane-2-ol 9-hydroxy-9-methyldecane-3,6-dione 8-hydroxy-8-methylnonane-3,6-dione OHarrow_forward
- Could you please explain whether my thinking is correct or incorrect regarding how I solved it? Please point out any mistakes in detail, with illustrations if needed.arrow_forwardWhat are the most proper reagents to achieve these products? سد 1. 2. OH ○ 1. BrMgC6H6; 2. H+ ○ 1. BrMgCH2CH2CH2CH2CH3; 2. H+ O 1. CH3CH2CHO; 2. H+ O 1. BrMgCH2CH3; 2. H+arrow_forwardProvide the IUPAC (systematic) name only for the following compound. Dashes, commas, and spaces must be correct. Harrow_forward
- Please use the nernst equation to genereate the Ion Selective Electrode Analysis standard curve within my excel spread sheet. Nernst Equation: E = Eo + m (ln a) Link: https://mnscu-my.sharepoint.com/:x:/g/personal/vi2163ss_go_minnstate_edu/EaREe1-PfGNKq1Cbink6kkYB5lBy05hEaE3mbGPUb22S6w?rtime=zQaSX3xY3Ugarrow_forwarda) b) c) H NaOH heat, dehydration + KOH heat, dehydration NaOH + (CH3)3CCHO heat, dehydration Pharrow_forwardshow mechanismarrow_forward
- Please draw by handarrow_forward3. Predict the major product and give a mechanism for the following reactions: (CH3)3COH/H₂SO4 a) b) NC CH₂O c) LOCH, (CH3)3COH/H2SO4 H,SO -OHarrow_forwardIndicate if the aldehyde shown reacts with the provided nucleophiles in acid or base conditions. a NaBH4 be Li eli -NH2 P(Ph3) f KCN g OH excess h CH3OH i NaCHCCH3arrow_forward
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