
EBK DATABASE SYSTEM CONCEPTS
7th Edition
ISBN: 9781260049268
Author: SILBERSCHATZ
Publisher: MCG COURSE
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Expert Solution & Answer
Chapter 7, Problem 14PE
Explanation of Solution
- Let F be a set of functional dependencies that hold on a schema R.
- Let σ= {R1, R2, . . . , Rn} be a dependency-preserving 3NF decomposition of R. Let X be a candidate key for R.
- Consider a legal instance r of R. Let j = ΠX(r) ⋈ΠR1 (r) ⋈ΠR2 (r) ⋈ΠRn (r). We want to prove that r = j.
- The user can claim that if t1 and t2 are two tuples in j such that t1[X] = t2[X], then t1 = t2. To prove this claim, we use the following inductive argument-
- Let F ′ = F1 ∪ F2 ∪ . . . ∪ Fn, where each Fi is the restriction of F to the schema Ri in s.
- Consider the use of the
algorithm given in Figure 8.8 to compute the closure of X under F ′ . We use induction on the number of times that the f or loop in this algorithm is executed.
- Basis : In the first step of the algorithm, result is assigned to X, and hence given that t1[X] = t2[X], we know that t1[result] = t2[result] is true.
- Induction Step : Let t1[result] = t2[result] be true at the end of the k th execution of the f or loop...
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Dijkstra's Algorithm (part 1). Consider the network shown below, and Dijkstra’s link-state algorithm. Here, we are interested in computing the least cost path from node E (note: the start node here is E) to all other nodes using Dijkstra's algorithm. Using the algorithm statement used in the textbook and its visual representation, complete the "Step 0" row in the table below showing the link state algorithm’s execution by matching the table entries (i), (ii), (iii), and (iv) with their values. Write down your final [correct] answer, as you‘ll need it for the next question.
4. |z + 5 - 5i| = 7
14.
dz,
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Chapter 7 Solutions
EBK DATABASE SYSTEM CONCEPTS
Ch. 7 - Prob. 1PECh. 7 - Prob. 2PECh. 7 - Explain how functional dependencies can be used to...Ch. 7 - Prob. 4PECh. 7 - Prob. 5PECh. 7 - Prob. 6PECh. 7 - Prob. 7PECh. 7 - Prob. 8PECh. 7 - Prob. 9PECh. 7 - Prob. 10PE
Ch. 7 - Prob. 11PECh. 7 - Prob. 12PECh. 7 - Prob. 13PECh. 7 - Prob. 14PECh. 7 - Prob. 15PECh. 7 - Prob. 16PECh. 7 - Prob. 17PECh. 7 - Prob. 18PECh. 7 - Prob. 19PECh. 7 - Prob. 20PECh. 7 - Prob. 21ECh. 7 - Prob. 22ECh. 7 -
Explain what is meant by repetition of...Ch. 7 -
Why are certain functional dependencies called...Ch. 7 - Prob. 25ECh. 7 - Prob. 26ECh. 7 - Prob. 27ECh. 7 - Prob. 28ECh. 7 - Prob. 29ECh. 7 - Prob. 30ECh. 7 - Prob. 32ECh. 7 - Prob. 33ECh. 7 - Prob. 35ECh. 7 - Prob. 36ECh. 7 - Prob. 37ECh. 7 - Prob. 38ECh. 7 - Prob. 39ECh. 7 - Prob. 40ECh. 7 - Prob. 41ECh. 7 - Prob. 42ECh. 7 - Prob. 43E
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