Explanation Given: A = [ − 2 0 1 3 ] Concept: A − 1 exists if | A | ≠ 0 . If A = [ a b c d ] and [ 1 0 p q 0 1 r s ] is the reduced form of the augmented matrix of A, then A − 1 = [ p q r s ] Calculation: | A | = | − 2 0 1 3 | = − 6 − 0 = − 6 | A | ≠ 0 , so A − 1 exists. Write the augmented matrix of A. [ − 2 0 1 0 1 3 0 1 ] Use row-elementary operation on the augmented matrix to reduce it in the form of the matrix, [ 1 0 p q 0 1 r s ] Interchange row 1 and row 2

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ISBN: 9780135676028

Author: BEECHER

Publisher: PEARSON

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Chapter 6.RE, Problem 40RE

To determine

To find:

A−1 for the matrix,

A=[−2013]

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Chapter 6.RE, Problem 39RE

Chapter 6.RE, Problem 41RE

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Chapter 6 Solutions

COLLEGE ALGEBRA-MML 18 WEEK ACCESS ONLY

Ch. 6.1 - Prob. 1VG Ch. 6.1 - Prob. 2VG Ch. 6.1 - Prob. 3VG Ch. 6.1 - Prob. 4VG Ch. 6.1 - Prob. 5VG Ch. 6.1 - Prob. 6VG Ch. 6.1 - Prob. 7VG Ch. 6.1 - Prob. 8VG Ch. 6.1 - Prob. 9VG Ch. 6.1 - Prob. 10VG

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A − 1 for the matrix, A = [ − 2 0 1 3 ]

To find: A−1 for the matrix, A=[−2013]

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Chapter 6 Solutions

To find:

A−1 for the matrix,

A=[−2013]