Explanation In case of CH 4 Total no. of valence electron is = 4 + ( 1 × 4 ) = 8 Least electronegative atom i.e. C atom will be the central atom 8 electrons will be used to form 4 bonds with H, hence no lone pair of electron as shown in the Lewis structure. In CH 4 there are four bond pairs, and no lone pair. The four pairs of electrons arrange themselves tetrahedrally, with a bond angle of 109.5 o . In case of H 2 O Total no

Study Guide And Selected Solutions Manual For Chemistry Format: Paperback

13th Edition

ISBN: 9780134553986

Author: Timberlake, Karen C

Publisher: Prentice Hall

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Chapter 6.8, Problem 6.76PP

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To compare: The Lewis structure of CH₄and H₂O molecules.

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Chapter 6.8, Problem 6.75PP

Chapter 6.8, Problem 6.77PP

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Chapter 6 Solutions

Study Guide And Selected Solutions Manual For Chemistry Format: Paperback

Ch. 6.1 - State the number of electrons that be must be lost...Ch. 6.1 - State the number of electrons that must be gained...Ch. 6.1 - State the number of electrons lost or gained when...Ch. 6.1 - Prob. 6.4PP Ch. 6.1 - Write the symbols for the ions with the following...Ch. 6.1 - Write the symbols for the ions with the following...Ch. 6.1 - Prob. 6.7PP Ch. 6.1 - State the number of protons and electrons in each...Ch. 6.1 - Write the symbol for the ion of each of the...Ch. 6.1 - Write the symbol for the ion of each of the...

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To compare: The Lewis structure of CH 4 and H 2 O molecules.

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To compare: The Lewis structure of CH4and H2O molecules.

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Chapter 6 Solutions

To compare: The Lewis structure of CH₄and H₂O molecules.