(a) Explanation Given Information: Provided polynomial is, 3 t 2 + 13 t + 4 The category of the polynomials are: (1) The difference of squares for numbers x and y x 2 − y 2 = ( x + y ) ( x − y ) (2) The sum of squares for numbers a and b that does not have common factor is a 2 + b 2 that should be prime for all real numbers (3) The difference of cube for numbers a and b is a 3 − b 3 = ( a − b ) ( a 2 + a b + b 2 ) (4) The sum of cubes for numbers a and b is, a 3 + b 3 = ( a + b ) ( a 2 − a b + b 2 ) (5) The perfect square trinomial: It should only have three terms and check that the first and third terms are perfect squares and have positive coefficients (b) To determine To calculate: The factor of the polynomial 3 t 2 + 13 t + 4 .

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ISBN: 9780073384511

Author: Julie Miller, Molly O'Neill, Nancy Hyde

Publisher: MCGRAW-HILL HIGHER EDUCATION

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Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.

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Chapter 6.6, Problem 9PRE

(a)

To determine

The category in which the remaining polynomial best fit if factor out the greatest common factor from the polynomial 3t2+13t+4. The categories are: difference of squares, sum of squares, difference of cubes, sum of cubes, trinomial (perfect square trinomial), trinomial (nonperfect square trinomial), four terms-grouping, none of these.

(b)

To determine

To calculate: The factor of the polynomial 3t2+13t+4.

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Chapter 6.6, Problem 8PRE

Chapter 6.6, Problem 10PRE

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Chapter 6 Solutions

Beginning and Intermediate Algebra

Ch. 6.1 - Find the GCF. 1. Ch. 6.1 - Find the GCF. 2. Ch. 6.1 - Prob. 3SP Ch. 6.1 - Prob. 4SP Ch. 6.1 - Prob. 5SP Ch. 6.1 - Find the GCF. a ( x + 2 ) and b ( x + 2 )Ch. 6.1 - Prob. 7SP Ch. 6.1 - Prob. 8SP Ch. 6.1 - Prob. 9SP Ch. 6.1 - Prob. 10SP

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Solution Summary: The author explains the category of the polynomial 3t2+13t+4 if factor out the greatest common factor.

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To calculate: The factor of the polynomial 3t2+13t+4.

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