Chapter 6.6, Problem 91E

(a)

To determine

To graph:The paths of a projectile launched from ground level at $\theta =60°$ and $v_0=88feet\text{per}second$, use the graph to approximate the maximum height and range of the projectile, and the initial velocity and path of projectile have the parametric equations as, $x=\left(v_0\cos \theta \right)t$ and $y=h+\left(v_0\sin \theta \right)t-16t^2$.

(b)

To determine

To graph:The paths of projectile launched from ground level at $\theta =60°$, $v_0=132feet\text{per}second$, and use the graph to approximate the maximum height and range of the projectile, and the initial velocity and path of projectile have the parametric equations as, $x=\left(v_0\cos \theta \right)t$ and $y=h+\left(v_0\sin \theta \right)t-16t^2$.

(c)

To determine

To graph:The paths of projectile launched from ground level at $\theta =45°$, $v_0=88feet\text{per}second$, and to approximate the maximum height and range of the projectile, and the initial velocity and path of projectile have the parametric equations as, $x=\left(v_0\cos \theta \right)t$ and $y=h+\left(v_0\sin \theta \right)t-16t^2$.

(d)

To determine

To graph:The paths of projectile launched from ground level at $\theta =45°$, $v_0=132feet/second$, and to approximate the maximum height and range of the projectile. The initial velocity and path of projectile have the parametric equations as, $x=\left(v_0\cos \theta \right)t$ and $y=h+\left(v_0\sin \theta \right)t-16t^2$.