Explanation Approach: Simple Harmonic Motion: If the equation describing the displacement y of an object at time t is y = a sin ⁡ ω t - c + b or y = a cos ⁡ ω t - c + b then the object is in simple harmonic motion. In this case, Amplitude a = a Period p = 2 π ω Frequency f = ω 2 π c represents the position of the object at time t = 0 . b represents the vertical shift. Calculation: Given: E A = 50 sin ⁡ 120 π t , E B = 50 sin ⁡ 120 π t - 5 π 4 Comparing the voltage equation for the generator A E To determine (b) To state: Whether the generators producing voltage in phase and find the angle of the armature in the second generator to be rotated counter-clockwise in order that the two generators produce voltage in phase.

4th Edition

ISBN: 8220100548512

Author: Watson

Publisher: CENGAGE L

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Chapter 6.6, Problem 62E

To determine

(a)

To find:

The voltage phase for generators and the phase difference if the voltage for each generator is modeled by EA=50sin⁡120πt EB=50sin⁡120πt-5π4.

To determine

(b)

To state:

Whether the generators producing voltage in phase and find the angle of the armature in the second generator to be rotated counter-clockwise in order that the two generators produce voltage in phase.

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Chapter 6.6, Problem 61E

Chapter 6.6, Problem 63E

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(a) To find: The voltage phase for generators and the phase difference if the voltage for each generator is modeled by E A = 50 sin ⁡ 120 π t E B = 50 sin ⁡ 120 π t - 5 π 4 .

Solution Summary: The author explains how to find the voltage phase for generators and the phase difference if each generator is modeled by E_A.

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(a)

To find:

The voltage phase for generators and the phase difference if the voltage for each generator is modeled by EA=50sin⁡120πt EB=50sin⁡120πt-5π4.

(b)

To state:

Whether the generators producing voltage in phase and find the angle of the armature in the second generator to be rotated counter-clockwise in order that the two generators produce voltage in phase.

Want to see the full answer?

Chapter 6 Solutions

(a) To find: The voltage phase for generators and the phase difference if the voltage for each generator is modeled by E A = 50 sin ⁡ 120 π t E B = 50 sin ⁡ 120 π t - 5 π 4 .

Solution Summary: The author explains how to find the voltage phase for generators and the phase difference if each generator is modeled by E_A.

Videos

(a) To find: The voltage phase for generators and the phase difference if the voltage for each generator is modeled by EA=50sin⁡120πt EB=50sin⁡120πt-5π4.

(b) To state: Whether the generators producing voltage in phase and find the angle of the armature in the second generator to be rotated counter-clockwise in order that the two generators produce voltage in phase.

Want to see the full answer?

Chapter 6 Solutions

(a)

To find:

The voltage phase for generators and the phase difference if the voltage for each generator is modeled by EA=50sin⁡120πt EB=50sin⁡120πt-5π4.

(b)

To state:

Whether the generators producing voltage in phase and find the angle of the armature in the second generator to be rotated counter-clockwise in order that the two generators produce voltage in phase.