
EBK 3N3-EBK: INDUSTRIAL MOTOR CONTROL
7th Edition
ISBN: 9780176919962
Author: Herman
Publisher: VST
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Question
Chapter 66, Problem 3RQ
To determine
The average open loop gain of the operational amplifier 741.
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H.W:
1-A Pitot tube is inserted in the pipe of 30 cm I.D. The static pressure head is 10 cm Hg vacuum,
and the stagnation pressure at center of the pipe is 0.981 N/cm2 gauge. Calculate the discharge
of water through the pipe if u/umax = 0.85. Take Cp = 0.98.
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temperature is 65.5°C. The Pitot tube is placed at the center of the duct and the reading R on the
manometer is 10.7 mm of water. A static pressure measurement obtained at the Pitot tube
position is 205 mm of water above atmospheric. Take Cp = 0.98, = 2.03 x 10-5 Pa.s
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4. The following assembly is made of an Aluminium rod (E = 500 MPa). The diameter of the
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A
400 mm
1400 kN
B
800 mm
(i) Is this a statically indeterminate problem? Why?
(ii) Can you draw the axial load diagram without first resolving the reaction forces at A and
C?
(iii) Determine the reaction forces at A and C.
(iv) Draw the axial load diagram.
(v) Determine the deformation at section BC.
Chapter 66 Solutions
EBK 3N3-EBK: INDUSTRIAL MOTOR CONTROL
Ch. 66 - Prob. 1RQCh. 66 - Prob. 2RQCh. 66 - Prob. 3RQCh. 66 - Prob. 4RQCh. 66 - Prob. 5RQCh. 66 - Prob. 6RQCh. 66 - Name two effects of negative feedback.Ch. 66 - Refer to Figure 668. If resistor R1 is 200 ohms...Ch. 66 - Refer to Figure 66–9. If resistor R1 is 470 ohms...Ch. 66 - What is the purpose of the hysteresis loop when...
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