EBK ELECTRICAL MOTOR CONTROLS FOR INTEG
5th Edition
ISBN: 8220101434760
Author: ROCKIS
Publisher: ATP
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Chapter 6.6, Problem 1CP
To determine
To explain: The abbreviation of “in. WC” stands for the unit of pressure switch.
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Twenty-five signals, ten of them have 3.4 kHz bandwidth, the other have bandwidth of 5 kHz
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Chapter 6 Solutions
EBK ELECTRICAL MOTOR CONTROLS FOR INTEG
Ch. 6.1 - Prob. 1CPCh. 6.1 - Prob. 2CPCh. 6.1 - Prob. 3CPCh. 6.1 - Prob. 4CPCh. 6.2 - Prob. 1CPCh. 6.2 - Prob. 2CPCh. 6.2 - Prob. 3CPCh. 6.2 - Prob. 4CPCh. 6.3 - Prob. 1CPCh. 6.3 - Prob. 2CP
Ch. 6.4 - Prob. 1CPCh. 6.4 - Prob. 2CPCh. 6.4 - Prob. 3CPCh. 6.4 - Prob. 4CPCh. 6.5 - Prob. 1CPCh. 6.5 - Prob. 2CPCh. 6.6 - Prob. 1CPCh. 6.6 - Prob. 2CPCh. 6.7 - Prob. 1CPCh. 6.7 - Prob. 2CPCh. 6.8 - Prob. 1CPCh. 6.8 - Prob. 2CPCh. 6.9 - Prob. 1CPCh. 6.9 - Prob. 2CPCh. 6.10 - Prob. 1CPCh. 6.10 - Prob. 2CPCh. 6.10 - Prob. 3CPCh. 6.10 - Prob. 4CP
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- An FDM is used to multiplex two groups of signals using AM-SSB, the first group contains 25 speech signals, each has maximum frequency of 4 kHz, the second group contains 15 music signals, each has maximum frequency of 10 kHz. A guard bandwidth of 500 Hz is used between each two signals and before the first one. 1. Find the BWmultiplexing 2. Find the BWtransmission if the multiplexing signal is modulated using AM-DSB-LC.arrow_forwardA single tone is modulated using FM transmitter. The SNR; at the input of the demodulator Is 20 dB. If the maximum frequency of the modulating signal is 4 kHz, and the maximum frequency deviation is 12 kHz, find the SNR, and the bandwidth (using Carson rule) at the following conditions: 1. For the given values of fm and Af. 2. If the amplitude of the modulating signal is increased by 80%. 3. If the amplitude of the modulating signal is decreased by 50%, and frequency of modulating signal is increased by 50%.arrow_forwardFM station of 100 MHz carrier frequency modulated by a 20 kHz sinusoid with an amplitude of 10 volt, so that the peak frequency deviation is 25 kHz determine: 1) The BW of the FM signal. 2) The approximated BW if the modulating signal amplitude is increased to 50 volt. 3) The approximated BW if the modulating signal frequency is increased by 70%. 4) The amplitude of the modulating signal if the BW is 65 kHz.arrow_forward
- b) The joint probability function for the random variables X and Y is given in Table below. Find a) the marginal probability function of X and Y. P(Y/X) and P(X/Y). c) P(X ≥ 2, Y ≤ 2) y 1 2 3 10.05 0.05 0.1 P(X, Y) = X 20.05 0.1 0.35 3 0 0.2 0.1arrow_forwardSuppose a random variable X as pmf / Px (x) = { %, x = 1, 2, 3, 0, otherwise. find constand c ①P(X = 1), P(X 7,2), PC1 3) C CDFarrow_forwardSuppose that a coin is tossed three so that the sample space is Let X represent the number of heads that can come up. i) Find the probability function corresponding to the random variable X. Assuming that the coin is fair ii) Find the distribution function for the random variable X. iii) Obtain its graph.arrow_forward
- Q9 A single-phase transformer, 2500 / 250 V, 50 kVA, 50 Hz has the following parameters, the Primary and secondary resistances are 0.8 ohm and 0.012 ohm respectively, the primary and secondary reactance are 4 ohm and 0.04 ohm respectively and the transformer gives 96% maximum efficiency at 75% full-load. The magnetizing component of-load current is 1.2 A on 2500 V side. 1- Draw the equivalent circuit referred to primary (H.V side) and inserts all the values in it 2- Find out Ammeter, voltmeter and wattmeter readings on open-circuit and short-circuit test. If supply is given to 2500 V side in both cases. Ans. O.C. Test (Vo= 2500 V, lo=1.24 A, Wo=781.25 w) S.C. Test (Vsc =164.924 V, Isc =20 A, Wsc =800 w )arrow_forwardQ2-A)- Enumerate the various losses in transformer. Explain how each loss varies with (Load current, supply voltage). B)- Draw the pharos diagram at load on primary side.arrow_forwardQ2- What are the parameters and loss that can be determined during open-circuit test of singlephase transformer. Draw the circuit diagram of open-circuit test and explain how can you calculate the Parameters and loss.arrow_forward
- Q2-Drive the condition of maximum efficiency of single-phase transformer. Q1- A 5 KVA, 500/250 V ,50 Hz, single phase transformer gave the following reading: O.C. Test: 250 V,2 A, 50 W (H.V. side open) S.C. Test: 25 V10 A, 60 W (L.V. side shorted) Determine: i) The efficiency on full load, 0.8 lagging p.f. ii) Draw the equivalent circuit referred to primary and insert all the values it.arrow_forwardQ2- Describe various losses in transformer. Explain how each loss varies with load current, supply voltagearrow_forwardQ1-A 12 KVA, 440/ 220 V, 50 Hz single phase transformer has 275 secondary turns. The no load current of transformer is 2A at power factor 0.375 when connected to 220 V, 50 Hz supply. The full load copper loss is 198.3 watt. Calculate a) Maximum value of flux in the core. b) Maximum efficiency at 0.8 lagging p.f c) KVA supply at maximum efficiencyarrow_forward
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