Explanation Write the energy conservation principle. E sys,f = E sys,i + W surr (I) Here, E sys,f is the final energy of the system, E sys,i is the initial energy of the system and W surr is the work done by the surroundings. Write the equation for the initial energy of the system. E sys,i = ( m p c 2 + K p ) + ( m e c 2 + K e ) + K ν ¯ Here, m p is the mass of the proton, c is the speed of light, K p is the kinetic energy of the proton, m e is the mass of the electron, K e is the kinetic energy of the electron and K ν ¯ is the kinetic energy of the anti-neutrino. Write the equation for the final energy of the system. E sys,f = m N c 2 + K N Here, m N is the mass of the neutron and K N is the kinetic energy of the neutron. Put the above two equations in equation (I). ( m p c 2 + K p ) + ( m e c 2 + K e ) + K ν ¯ = m N c 2 + K N + W surr No work is done by the surroundings. Substitute 0 for W surr in the above equation. ( m p c 2 + K p ) + ( m e c 2 + K e ) + K ν ¯ = m N c 2 + K N + 0 ( m p c 2 + K p ) + ( m e c 2 + K e ) + K ν ¯ = m N c 2 + K N (II) Conclusion: The value of m p c 2 is 938

4th Edition

ISBN: 9781118875865

Author: Ruth W. Chabay, Bruce A. Sherwood

Publisher: WILEY

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Nuclear interactions

In nature, there are certain rules and standards for an interaction. These interactions are universally accepted. There are four types of interactions:

Question

Chapter 6.5, Problem 8CP

To determine

The fraction of the original neutron’s rest energy that is converted into kinetic energy.

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Chapter 6.4, Problem 7CP

Chapter 6.7, Problem 9CP

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Chapter 6 Solutions

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