Explanation Given: The mass of model train and the length of electric track is given by: m = 0.5 k g l = 3 m The force is F ( x ) = ( 3 x − x 2 ) N Concept used: The work-energy theorem is W = 1 2 m v 2 Calculation: The given force is F ( x ) = ( 3 x − x 2 ) N . Therefore, the work performed when the train reaches the end of 3m long electric track is, W = ∫ 0 3 ( 3 x − x 2 ) d x W = [ 3 2 x 2 − x 3 3 ] 0 3 W = [ 3 2 ( 3 − 0 ) 2 − ( 3 − 0 ) 3 3 ] W = [ 27 2 − 27 3 ] W = 9 2 joule Let v 1 , v 2 be the initial and final velocities of the train

4th Edition

ISBN: 9781319379421

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 6.5, Problem 40E

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the velocity of the train when it reaches end of the track.

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Chapter 6.5, Problem 39E

Chapter 6.5, Problem 41E

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Chapter 6 Solutions

CALCULUS 4E (HC) W/ ACHIEVE ACCESS

Ch. 6.1 - Prob. 1PQ Ch. 6.1 - Prob. 2PQ Ch. 6.1 - Prob. 3PQ Ch. 6.1 - Prob. 4PQ Ch. 6.1 - Prob. 5PQ Ch. 6.1 - Prob. 6PQ Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E

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the velocity of the train when it reaches end of the track.

Solution Summary: The author calculates the velocity of the train when it reaches the end of 3m long electric track.

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To calculate: the velocity of the train when it reaches end of the track.

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Chapter 6 Solutions

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the velocity of the train when it reaches end of the track.