Explanation Definition used: Definition 1: The quotient of two fractions is computed by reciprocal of the second fraction and then proceeding as in multiplication. Definition 2: “The product of two fractions is a fraction whose numerator is the product of the numerators and denominator is the product of the denominators of the given fractions.” Calculation: The given expression is 6 T 2 − N T − N 2 2 V 2 − 9 V − 35 8 T 2 − 2 N T − N 2 20 V 2 + 26 V − 60 . By the definition stated above, the algebraic fraction can be written as 6 T 2 − N T − N 2 2 V 2 − 9 V − 35 × 20 V 2 + 26 V − 60 8 T 2 − 2 N T − N 2 . Factor the numerator and denominator of the above expression as follows. 6 T 2 − N T − N 2 2 V 2 − 9 V − 35 8 T 2 − 2 N T − N 2 20 V 2 + 26 V − 60 = ( 6 T 2 − N T − N 2 ) ( 20 V 2 + 26 V − 60 ) ( 2 V 2 − 9 V − 35 ) ( 8 T 2 − 2 N T − N 2 ) [ ∵ a b ⋅ c d = a c b d ] = ( 6 T 2 − 3 N T + 2 N T − N 2 ) ( 2 ) ( 10 V 2 − 12 V + 25 V − 30 ) ( 2 V 2 − 14 V + 5 V − 35 ) ( 8 T 2 − 4 N T + 2 N T − N 2 ) = 2 ( 3 T ( 2 T − N ) + N ( 2 T − N ) ) ( 2 V ( 5 V − 6

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 6.5, Problem 29E

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To simplify: The expression 6T2−NT−N22V2−9V−358T2−2NT−N220V2+26V−60 that involving multiplication and division.

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Chapter 6.5, Problem 28E

Chapter 6.5, Problem 30E

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Chapter 6 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 6.1 - Prob. 1PE Ch. 6.1 - Prob. 2PE Ch. 6.1 - Prob. 3PE Ch. 6.1 - Prob. 4PE Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E

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The expression 6 T 2 − N T − N 2 2 V 2 − 9 V − 35 8 T 2 − 2 N T − N 2 20 V 2 + 26 V − 60 that involving multiplication and division.

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To simplify: The expression 6T2−NT−N22V2−9V−358T2−2NT−N220V2+26V−60 that involving multiplication and division.

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Chapter 6 Solutions