Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 65, Problem 1AR
To determine

Conversion of 356.4 square inches into square feet.

Expert Solution & Answer
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Answer to Problem 1AR

356.4 square inches is equal to 2.5 square feet.

Explanation of Solution

Given information:

Area of any shape is given as 356.4 square inches.

Calculation:

In the geometrical scale:

1 foot is equal to 12 inches.

So, the value of 1 inch is equal to 112=0.083feet

And the value of 1 square inch is equal to 0.083×0.083=0.006944squarefeet.

Hence, the value of 356.4 square inches is =

  365.4×0.006944=2.5squarefeet.

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Chapter 65 Solutions

Mathematics For Machine Technology

Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The following Exercises 7 through 19 involve...Ch. 65 - The cross section of a dovetail slide is shown....Ch. 65 - Compute the area of the pattern shown. Round the...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - The following Exercises 22 through 27 involve...Ch. 65 - Find the area of each of the segments ACB for...Ch. 65 - Prob. 29ARCh. 65 - Find the area of each of the segments ACB for...Ch. 65 - Find the area of the shaded segment shown. Round...Ch. 65 - A circular plate with a 15.00-inch radius is cut...Ch. 65 - Compute the cross-sectional area of the grooved...Ch. 65 - Find the area of the pattern shown. Round the...Ch. 65 - Prob. 35ARCh. 65 - Express each volume in Exercises 35 through 40 as...Ch. 65 - Prob. 37ARCh. 65 - Express each volume in Exercises 35 through 40 as...Ch. 65 - Express each volume in Exercises 35 through 40 as...Ch. 65 - Express each volume in Exercises 35 through 40 as...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 45ARCh. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 47ARCh. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 49ARCh. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 51ARCh. 65 - Prob. 52ARCh. 65 - Prob. 53ARCh. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 56ARCh. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Solve these prism and cylinder exercises. Where...Ch. 65 - Prob. 60ARCh. 65 - Prob. 61ARCh. 65 - Diameter 9.050 centimeters; Volume Round the...Ch. 65 - Prob. 63ARCh. 65 - Volume = 42.98 cubic inches; Diameter = Round the...Ch. 65 - Volume = 775 cubic centimeters; Diameter = Round...Ch. 65 - The side view of a steel roundhead (hemisphere)...Ch. 65 - Prob. 67ARCh. 65 - A hollow glass sphere has an outside circumference...Ch. 65 - Prob. 69ARCh. 65 - Compute the number of cubic centimeters of iron...
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