ELEMENTARY STAT.USING EXCEL-COMBO CARD
7th Edition
ISBN: 9780137376643
Author: Triola
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 6.4, Problem 8BSC
a.
To determine
To Find: The
b.
To determine
To Find: The probability that the mean weight gain of 4 randomly selected male students between 0.5 kg and 2.5 kg.
c.
To determine
To Find: The reason behind getting a normal distribution of sample means instead of having a sample of size less than 30.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
5. Let X be a positive random variable with finite variance, and let A = (0, 1).
Prove that
P(X AEX) 2 (1-A)² (EX)²
EX2
6. Let, for p = (0, 1), and xe R. X be a random variable defined as follows:
P(X=-x) = P(X = x)=p. P(X=0)= 1-2p.
Show that there is equality in Chebyshev's inequality for X.
This means that Chebyshev's inequality, in spite of being rather crude, cannot be
improved without additional assumptions.
4. Prove that, for any random variable X, the minimum of EIX-al is attained for
a = med (X).
Chapter 6 Solutions
ELEMENTARY STAT.USING EXCEL-COMBO CARD
Ch. 6.1 - 1. Normal Distribution What’s wrong with the...Ch. 6.1 - Prob. 2BSCCh. 6.1 - Prob. 3BSCCh. 6.1 - Prob. 4BSCCh. 6.1 - Continuous Uniform Distribution. In Exercises 5–8,...Ch. 6.1 - Continuous Uniform Distribution. In Exercises 5–8,...Ch. 6.1 - Prob. 7BSCCh. 6.1 - Prob. 8BSCCh. 6.1 - Standard Normal Distribution. In Exercises 9–12,...Ch. 6.1 - Standard Normal Distribution. In Exercises 9–12,...
Ch. 6.1 - Standard Normal Distribution. In Exercises 9–12,...Ch. 6.1 - Standard Normal Distribution. In Exercises 9–12,...Ch. 6.1 - Standard Normal Distribution. In Exercises 13–16,...Ch. 6.1 - Standard Normal Distribution. In Exercises 13–16,...Ch. 6.1 - Standard Normal Distribution. In Exercises 13–16,...Ch. 6.1 - Standard Normal Distribution. In Exercises 13–16,...Ch. 6.1 - Prob. 17BSCCh. 6.1 - Prob. 18BSCCh. 6.1 - Prob. 19BSCCh. 6.1 - Prob. 20BSCCh. 6.1 - Prob. 21BSCCh. 6.1 - Prob. 22BSCCh. 6.1 - Prob. 23BSCCh. 6.1 - Prob. 24BSCCh. 6.1 - Prob. 25BSCCh. 6.1 - Prob. 26BSCCh. 6.1 - Prob. 27BSCCh. 6.1 - Prob. 28BSCCh. 6.1 - Prob. 29BSCCh. 6.1 - Prob. 30BSCCh. 6.1 - Prob. 31BSCCh. 6.1 - Prob. 32BSCCh. 6.1 - Prob. 33BSCCh. 6.1 - Prob. 34BSCCh. 6.1 - Prob. 35BSCCh. 6.1 - Prob. 36BSCCh. 6.1 - Finding Bone Density Scores. In Exercises 37–40...Ch. 6.1 - Prob. 38BSCCh. 6.1 - Prob. 39BSCCh. 6.1 - Prob. 40BSCCh. 6.1 - Prob. 41BSCCh. 6.1 - Prob. 42BSCCh. 6.1 - Prob. 43BSCCh. 6.1 - Prob. 44BSCCh. 6.1 - Prob. 45BSCCh. 6.1 - Prob. 46BSCCh. 6.1 - Prob. 47BSCCh. 6.1 - Prob. 48BSCCh. 6.1 - Prob. 49BBCh. 6.1 - Prob. 50BBCh. 6.2 - Prob. 1BSCCh. 6.2 - Prob. 2BSCCh. 6.2 - Prob. 3BSCCh. 6.2 - Prob. 4BSCCh. 6.2 - IQ Scores. In Exercises 5–8, find the area of the...Ch. 6.2 - IQ Scores. In Exercises 5–8, find the area of the...Ch. 6.2 - Prob. 7BSCCh. 6.2 - IQ Scores. In Exercises 5–8, find the area of the...Ch. 6.2 - IQ Scores. In Exercises 9–12, find the indicated...Ch. 6.2 - IQ Scores. In Exercises 9–12, find the indicated...Ch. 6.2 - Prob. 11BSCCh. 6.2 - Prob. 12BSCCh. 6.2 - Prob. 13BSCCh. 6.2 - Prob. 14BSCCh. 6.2 - Prob. 15BSCCh. 6.2 - Prob. 16BSCCh. 6.2 - Prob. 17BSCCh. 6.2 - Prob. 18BSCCh. 6.2 - Prob. 19BSCCh. 6.2 - Prob. 20BSCCh. 6.2 - Prob. 21BSCCh. 6.2 - Prob. 22BSCCh. 6.2 - Prob. 23BSCCh. 6.2 - Prob. 24BSCCh. 6.2 - Prob. 25BSCCh. 6.2 - In Exercises 21–24, use these parameters (based on...Ch. 6.2 - In Exercises 21–24, use these parameters (based on...Ch. 6.2 - Prob. 28BSCCh. 6.2 - Prob. 29BSCCh. 6.2 - Prob. 30BSCCh. 6.2 - Prob. 31BSCCh. 6.2 - Prob. 32BSCCh. 6.2 - Prob. 33BSCCh. 6.2 - Prob. 34BSCCh. 6.2 - Prob. 35BSCCh. 6.2 - Prob. 36BSCCh. 6.2 - Prob. 37BBCh. 6.2 - Prob. 38BBCh. 6.3 - Prob. 1BSCCh. 6.3 - Prob. 2BSCCh. 6.3 - Prob. 3BSCCh. 6.3 - Prob. 4BSCCh. 6.3 - Prob. 5BSCCh. 6.3 - Prob. 6BSCCh. 6.3 - Prob. 7BSCCh. 6.3 - Prob. 8BSCCh. 6.3 - Prob. 9BSCCh. 6.3 - In Exercises 7–10, use the same population of {4,...Ch. 6.3 - Prob. 11BSCCh. 6.3 - Prob. 12BSCCh. 6.3 - Prob. 13BSCCh. 6.3 - Prob. 14BSCCh. 6.3 - Prob. 15BSCCh. 6.3 - Prob. 16BSCCh. 6.3 - Prob. 17BSCCh. 6.3 - Prob. 18BSCCh. 6.3 - Prob. 19BBCh. 6.3 - Prob. 20BBCh. 6.4 - Prob. 1BSCCh. 6.4 - Prob. 2BSCCh. 6.4 - Prob. 3BSCCh. 6.4 - Prob. 4BSCCh. 6.4 - Prob. 5BSCCh. 6.4 - Prob. 6BSCCh. 6.4 - Prob. 7BSCCh. 6.4 - Prob. 8BSCCh. 6.4 - Prob. 9BSCCh. 6.4 - Prob. 10BSCCh. 6.4 - Prob. 11BSCCh. 6.4 - Prob. 12BSCCh. 6.4 - Prob. 13BSCCh. 6.4 - Prob. 14BSCCh. 6.4 - Prob. 15BSCCh. 6.4 - Prob. 16BSCCh. 6.4 - Prob. 17BSCCh. 6.4 - Prob. 18BSCCh. 6.4 - Prob. 19BSCCh. 6.4 - Prob. 20BBCh. 6.5 - Prob. 1BSCCh. 6.5 - Prob. 2BSCCh. 6.5 - Prob. 3BSCCh. 6.5 - Prob. 4BSCCh. 6.5 - Prob. 5BSCCh. 6.5 - Prob. 6BSCCh. 6.5 - Prob. 7BSCCh. 6.5 - Prob. 8BSCCh. 6.5 - Prob. 9BSCCh. 6.5 - Prob. 10BSCCh. 6.5 - Prob. 11BSCCh. 6.5 - Prob. 12BSCCh. 6.5 - Prob. 13BSCCh. 6.5 - Prob. 14BSCCh. 6.5 - Prob. 15BSCCh. 6.5 - Prob. 16BSCCh. 6.5 - Prob. 17BSCCh. 6.5 - Prob. 18BSCCh. 6.5 - Prob. 19BSCCh. 6.5 - Prob. 20BSCCh. 6.5 - Prob. 21BBCh. 6.5 - Prob. 22BBCh. 6 - Prob. 1CQQCh. 6 - Prob. 2CQQCh. 6 - Prob. 3CQQCh. 6 - Prob. 4CQQCh. 6 - Prob. 5CQQCh. 6 - Prob. 6CQQCh. 6 - Prob. 7CQQCh. 6 - Prob. 8CQQCh. 6 - Prob. 9CQQCh. 6 - Prob. 10CQQCh. 6 - Prob. 1RECh. 6 - Prob. 2RECh. 6 - Prob. 3RECh. 6 - Prob. 4RECh. 6 - Prob. 5RECh. 6 - Prob. 6RECh. 6 - Prob. 7RECh. 6 - Prob. 8RECh. 6 - Prob. 9RECh. 6 - Prob. 10RECh. 6 - Prob. 1CRECh. 6 - Prob. 2CRECh. 6 - Prob. 3CRECh. 6 - Prob. 4CRECh. 6 - Prob. 5CRECh. 6 - Prob. 1FDD
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- 8. Recall, from Sect. 2.16.4, the likelihood ratio statistic, Ln, which was defined as a product of independent, identically distributed random variables with mean 1 (under the so-called null hypothesis), and the, sometimes more convenient, log-likelihood, log L, which was a sum of independent, identically distributed random variables, which, however, do not have mean log 1 = 0. (a) Verify that the last claim is correct, by proving the more general statement, namely that, if Y is a non-negative random variable with finite mean, then E(log Y) log(EY). (b) Prove that, in fact, there is strict inequality: E(log Y) < log(EY), unless Y is degenerate. (c) Review the proof of Jensen's inequality, Theorem 5.1. Generalize with a glimpse on (b).arrow_forward3. Prove that, for any random variable X, the minimum of E(X - a)² is attained for a = EX. Provedarrow_forward7. Cantelli's inequality. Let X be a random variable with finite variance, o². (a) Prove that, for x ≥ 0, P(X EX2x)≤ 02 x² +0² 202 P(|X - EX2x)<≤ (b) Find X assuming two values where there is equality. (c) When is Cantelli's inequality better than Chebyshev's inequality? (d) Use Cantelli's inequality to show that med (X) - EX ≤ o√√3; recall, from Proposition 6.1, that an application of Chebyshev's inequality yields the bound o√√2. (e) Generalize Cantelli's inequality to moments of order r 1.arrow_forward
- The college hiking club is having a fundraiser to buy new equipment for fall and winter outings. The club is selling Chinese fortune cookies at a price of $2 per cookie. Each cookie contains a piece of paper with a different number written on it. A random drawing will determine which number is the winner of a dinner for two at a local Chinese restaurant. The dinner is valued at $32. Since fortune cookies are donated to the club, we can ignore the cost of the cookies. The club sold 718 cookies before the drawing. Lisa bought 13 cookies. Lisa's expected earnings can be found by multiplying the value of the dinner by the probability that she will win. What are Lisa's expected earnings? Round your answer to the nearest cent.arrow_forwardThe Honolulu Advertiser stated that in Honolulu there was an average of 659 burglaries per 400,000 households in a given year. In the Kohola Drive neighborhood there are 321 homes. Let r be the number of homes that will be burglarized in a year. Use the formula for Poisson distribution. What is the value of p, the probability of success, to four decimal places?arrow_forwardThe college hiking club is having a fundraiser to buy new equipment for fall and winter outings. The club is selling Chinese fortune cookies at a price of $2 per cookie. Each cookie contains a piece of paper with a different number written on it. A random drawing will determine which number is the winner of a dinner for two at a local Chinese restaurant. The dinner is valued at $32. Since fortune cookies are donated to the club, we can ignore the cost of the cookies. The club sold 718 cookies before the drawing. Lisa bought 13 cookies. Lisa's expected earnings can be found by multiplying the value of the dinner by the probability that she will win. What are Lisa's expected earnings? Round your answer to the nearest cent.arrow_forward
- What was the age distribution of nurses in Great Britain at the time of Florence Nightingale? Thanks to Florence Nightingale and the British census of 1851, we have the following information (based on data from the classic text Notes on Nursing, by Florence Nightingale). Note: In 1851 there were 25,466 nurses in Great Britain. Furthermore, Nightingale made a strict distinction between nurses and domestic servants. Use a histogram and graph the probability distribution. Using the graph of the probability distribution determine the probability that a British nurse selected at random in 1851 would be 40 years of age or older. Round your answer to nearest thousandth. Age range (yr) 20–29 30–39 40–49 50–59 60–69 70–79 80+ Midpoint (x) 24.5 34.5 44.5 54.5 64.5 74.5 84.5 Percent of nurses 5.7% 9.7% 19.5% 29.2% 25.0% 9.1% 1.8%arrow_forwardWhat was the age distribution of nurses in Great Britain at the time of Florence Nightingale? Thanks to Florence Nightingale and the British census of 1851, we have the following information (based on data from the classic text Notes on Nursing, by Florence Nightingale). Note: In 1851 there were 25,466 nurses in Great Britain. Furthermore, Nightingale made a strict distinction between nurses and domestic servants. Use a histogram and graph the probability distribution. Using the graph of the probability distribution determine the probability that a British nurse selected at random in 1851 would be 40 years of age or older. Round your answer to nearest thousandth. Age range (yr) 20–29 30–39 40–49 50–59 60–69 70–79 80+ Midpoint (x) 24.5 34.5 44.5 54.5 64.5 74.5 84.5 Percent of nurses 5.7% 9.7% 19.5% 29.2% 25.0% 9.1% 1.8%arrow_forwardThere are 4 radar stations and the probability of a single radar station detecting an enemy plane is 0.55. Make a histogram for the probability distribution.arrow_forward
- show all stepsarrow_forwardMost people know that the probability of getting a head when you flip a fair coin is . You want to use the relative frequency of the event to show that the probability is . How many times should you simulate flipping the coin in the experiment? Would it be better to use 300 trials or 3000 trials? Explain.arrow_forwardThe qualified applicant pool for eight management trainee positions consists of ten women and six men. How many different groups of applicants can be selected for the positionsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGAL
Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage
Holt Mcdougal Larson Pre-algebra: Student Edition...
Algebra
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Glencoe Algebra 1, Student Edition, 9780079039897...
Algebra
ISBN:9780079039897
Author:Carter
Publisher:McGraw Hill
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:9781133382119
Author:Swokowski
Publisher:Cengage
Statistics 4.1 Point Estimators; Author: Dr. Jack L. Jackson II;https://www.youtube.com/watch?v=2MrI0J8XCEE;License: Standard YouTube License, CC-BY
Statistics 101: Point Estimators; Author: Brandon Foltz;https://www.youtube.com/watch?v=4v41z3HwLaM;License: Standard YouTube License, CC-BY
Central limit theorem; Author: 365 Data Science;https://www.youtube.com/watch?v=b5xQmk9veZ4;License: Standard YouTube License, CC-BY
Point Estimate Definition & Example; Author: Prof. Essa;https://www.youtube.com/watch?v=OTVwtvQmSn0;License: Standard Youtube License
Point Estimation; Author: Vamsidhar Ambatipudi;https://www.youtube.com/watch?v=flqhlM2bZWc;License: Standard Youtube License