Explanation The free body diagram of gear and shaft is shown below The symmetry of figure 1 gives the relation between A y and H y A y = H y = 1 2 F J K (I) Here, A y and H y are the components of force as shown in figure 1, and F J K is the force exerted by the center rod The free body diagram of grip arm is given below as figure 2 The y component of force under equilibrium, is ∑ F y = 15 17 B − A y = 0 (II) Here, B is the force at point B Write the expression for moment at D using figure 3 ∑ M D = F × d ⊥ (III) Here, F is the force, d ⊥ is the perpendicular distance between D and point where force is acting, and M D is the moment at D At equilibrium the moment at D will be zero ∑ M D = F × d ⊥ = 0 (IV) Write the complete expression for the total moment at D using figure P6 .144 under equilibrium is ∑ M D = A y ( 80 mm- ( 80 mm+60 mm − 95 mm ) ) − A x ( 400 mm ) = 0 (V) Here, A x and A y are the components of force at A . Consider the force along the x axis, F x , at equilibrium all forces along x axis will balances ∑ F x = 8 7 B − A x − D x − C = 0 (VI) Here, D x is the is the x component of force Conclusion: Substitute 4800 N for F J K in equation (I) A y = H y = 1 2 4800 N = 2400 N Substitute 2400 N for B in equation (II) ∑ F y = 15 17 B − 2400 N = 0

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ISBN: 9781265566296

Author: BEER

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Chapter 6.4, Problem 6.144P

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All forces acting on grip arm ABC.

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Chapter 6.4, Problem 6.143P

Chapter 6.4, Problem 6.145P

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All forces acting on grip arm A B C .

Solution Summary: The author explains the forces acting on grip arm ABC. The free body diagram of gear and shaft is shown below.

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