Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 64, Problem 4A
Convert 12.02 sq in. to square centimeters.
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Chapter 64 Solutions
Mathematics For Machine Technology
Ch. 64 - In order to make a conical duct a circular sheet...Ch. 64 - Prob. 2ACh. 64 - Prob. 3ACh. 64 - Convert 12.02 sq in. to square centimeters.Ch. 64 - Prob. 5ACh. 64 - Prob. 6ACh. 64 - Prob. 7ACh. 64 - Compute the volume of each sphere 7 through 14....Ch. 64 - Prob. 9ACh. 64 - Compute the volume of each sphere 7 through 14....
Ch. 64 - Prob. 11ACh. 64 - Compute the volume of each sphere 7 through 14....Ch. 64 - Prob. 13ACh. 64 - Compute the volume of each sphere 7 through 14....Ch. 64 - Prob. 15ACh. 64 - Solve these exercise. A vat in the shape of a...Ch. 64 - Prob. 17ACh. 64 - Solve these exercises. A company produces...Ch. 64 - Solve these exercises. Pieces in the shape of...Ch. 64 - Solve these exercises. A plastic products...Ch. 64 - Solve these exercises. Find the weight of the...Ch. 64 - Compute the capacity, in liters, of the container...Ch. 64 - A seamless brass tube and brass flange assembly is...Ch. 64 - Find the number of cubic centimeters of material...Ch. 64 - Find the weight of the cast-iron angle iron shown....Ch. 64 - Prob. 26ACh. 64 - Prob. 27ACh. 64 - Compute the number of cubic centimeters of...
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- Find the area bounded by f(x) = sin x, g(x) = cos x in the first quadrant.arrow_forward1. Matrix Operations Given: A = [ 33 ]A-[3-321] -3 B = [342]B-[3-41-2] (a) A² A2 Multiply A× A: -3 = (3 x 32x-3) (3 x 22 x 1) | = |[19–63 |-9-3 -6+21] = A² = 33 33 1-3×3+1x-3) (-3×2+1x1) [12]A2=[3-321][3-321]=[(3×3+2x-3)(-3×3+1x-3)(3×2+2×1)(-3×2+1×1)]=[9-6-9-36+2-6+1 ]=[3-128-5] (b) | A ||A| Determinant of A | A | (3 × 1) (2 x-3)=3+ 6 = 9|A|=(3×1)-(2x-3)=3+6=9 (c) Adjoint of A Swap diagonal elements and change sign of off-diagonals: A = [33], so adj (A) = |¯²]A=[3-321], so adj(A)=[13–23] -3 (d) B-¹B-1 First find | B ||B|: |B | (3x-2)- (1 × -4) = -6 + 4 = −2|B|=(3x-2)-(1x-4)=-6+4=-2 Then the adjoint of B: adj (B) = [² 3 adj(B)=[-24-13] Now, B-1 1 = |B| · adj (B) = 1 [²¯¯³¹³] = [2₂ B 0.5 |B-1=|B|1-adj(B)=-21[-24-13]=[1-20.5-1.5] 2. (a) Matrix Method: Solve (2x + 3y = 6 (2x-3y=14 {2x+3y=62x-3y=14 Matrix form: 22 33-22 = [223-3][xy]=[614] Find inverse of coefficient matrix: Determinant: | M | (2x-3) - (3 x 2) = -6 -6 = -12|M|=(2x-3)-(3×2)=-6-6=-12 Adjoint: adj(M) = [3]adj(M)-[-3-2-32] So…arrow_forwardQuestions An insurance company's cumulative incurred claims for the last 5 accident years are given in the following table: Development Year Accident Year 0 2018 1 2 3 4 245 267 274 289 292 2019 255 276 288 294 2020 265 283 292 2021 263 278 2022 271 It can be assumed that claims are fully run off after 4 years. The premiums received for each year are: Accident Year Premium 2018 306 2019 312 2020 318 2021 326 2022 330 You do not need to make any allowance for inflation. 1. (a) Calculate the reserve at the end of 2022 using the basic chain ladder method. (b) Calculate the reserve at the end of 2022 using the Bornhuetter-Ferguson method. 2. Comment on the differences in the reserves produced by the methods in Part 1.arrow_forward
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