Explanation Given information: The equation r = 1 − 2 sin θ . Graph: The equation r = 1 − 2 sin θ . Applying test for symmetry, Polar axis: Replace θ with − θ in r = 1 − 2 sin θ , r = 1 − 2 sin θ = 1 − 2 sin ( − θ ) = 1 + 2 sin θ The polar equation changes when θ replace with − θ , the graph is may be or may not be symmetric with respect to the polar axis. The line: Replace θ = π 2 Replace ( r , θ ) by ( − r , − θ ) in r = 1 − 2 sin θ − r = 1 − 2 sin ( − θ ) − r = 1 + 2 sin θ r = − 1 − 2 sin θ The polar equation changes when θ replace with ( − r , − θ ) , the graph is may or may not be symmetric With respect to the line θ = π 2

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Chapter 6.4, Problem 3CP

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To graph: Graph the equation r=1−2sinθ.

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Chapter 6.4, Problem 2CP

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Chapter 6 Solutions

Pearson eText for Precalculus Essentials -- Instant Access (Pearson+)

Ch. 6.1 - Check Point 1 Solve the triangle shown in Figure...Ch. 6.1 - Check Point 2 Solve triangle ABC if , and b = 12....Ch. 6.1 - Check Point 3 Solve triangle ABC if A = a = 33,...Ch. 6.1 - Prob. 4CP Ch. 6.1 - Prob. 5CP Ch. 6.1 - Check Point 6 Find the area of a triangle having...Ch. 6.1 - Prob. 7CP Ch. 6.1 - Fill in each blank so that the resulting statement...Ch. 6.1 - Prob. 2CVC Ch. 6.1 - Prob. 3CVC

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To graph: Graph the equation r = 1 − 2 sin θ .

To graph: Graph the equation r=1−2sinθ.

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Chapter 6 Solutions