The approximated value of y ( 1.2 ) for initial value problem x 2 y ″ − 2 x y ′ + 2 y = 0 , y ( 1 ) = 4 and y ′ ( 1 ) = 9 using step size h = 0.1 and also compare the obtained value with actual value.

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Answer 1

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Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

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Answer 2

Question

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

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Answer 3

Question

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

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Answer 4

Question

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

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Answer 5

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

Answer 6

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

Answer 7

Chapter 6.4, Problem 2E

To determine

The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 6.1 - Prob. 1E Ch. 6.1 - Prob. 2E Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - Prob. 8E Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

The approximated value of y ( 1.2 ) for initial value problem x 2 y ″ − 2 x y ′ + 2 y = 0 , y ( 1 ) = 4 and y ′ ( 1 ) = 9 using step size h = 0.1 and also compare the obtained value with actual value.

Solution Summary: The author calculates the approximated value of y(1.2) for the first order linear differential equation.

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The approximated value of y(1.2) for initial value problem x2y″−2xy′+2y=0, y(1)=4 and y′(1)=9 using step size h=0.1 and also compare the obtained value with actual value.

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