Chapter 6.3, Problem 6.6PP

Interpretation Introduction

Interpretation:

The molarity of $2.33gKCl$ when dissolved in $2.50\times {10}^{3}mL$ of solution has to be calculated.

Concept Introduction:

Number of mols can be calculated as follows,

    Number of mols $,n=\frac{givenmass}{molecularmass}$

Molarity $\left(\text{M}\right)$ can be calculated using the given equation.

    $\text{M}\text{=}\frac{\text{mol}\text{solute}}{\text{L}\text{solution}}$