Chapter 6.3, Problem 33ES

1 pts Let F and G be vector fields such that ▼ × F(0, 0, 0) = (0.76, -9.78, 3.29), G(0, 0, 0) = (−3.99, 6.15, 2.94), and G is irrotational. Then sin(5V (F × G)) at (0, 0, 0) is Question 1 -0.246 0.072 -0.934 0.478 -0.914 -0.855 0.710 0.262 .

Answer the number questions with the following answers  +/- 2 sqrt(2) +/- i sqrt(6) (-3 +/-3 i sqrt(3))/4 +/-1 +/- sqrt(6) +/- 2/3 sqrt(3) 4 -3 +/- 3 i sqrt(3)

2. Answer the following questions. (A) [50%] Given the vector field F(x, y, z) = (x²y, e", yz²), verify the differential identity Vx (VF) V(V •F) - V²F (B) [50%] Remark. You are confined to use the differential identities. Let u and v be scalar fields, and F be a vector field given by F = (Vu) x (Vv) (i) Show that F is solenoidal (or incompressible). (ii) Show that G = (uvv – vVu) is a vector potential for F.

A driver is traveling along a straight road when a buffalo runs into the street. This driver has a reaction time of 0.75 seconds. When the driver sees the buffalo he is traveling at 44 ft/s, his car can decelerate at 2 ft/s^2 when the brakes are applied. What is the stopping distance between when the driver first saw the buffalo, to when the car stops.

Topic 2 Evaluate S x dx, using u-substitution. Then find the integral using 1-x2 trigonometric substitution. Discuss the results! Topic 3 Explain what an elementary anti-derivative is. Then consider the following ex integrals: fed dx x 1 Sdx In x Joseph Liouville proved that the first integral does not have an elementary anti- derivative Use this fact to prove that the second integral does not have an elementary anti-derivative. (hint: use an appropriate u-substitution!)

1. Given the vector field F(x, y, z) = -xi, verify the relation 1 V.F(0,0,0) = lim 0+ volume inside Se ff F• Nds SE where SE is the surface enclosing a cube centred at the origin and having edges of length 2€. Then, determine if the origin is sink or source.

4 3 2 -5 4-3 -2 -1 1 2 3 4 5 12 23 -4 The function graphed above is: Increasing on the interval(s) Decreasing on the interval(s)

Question 4 The plot below represents the function f(x) 8 7 3 pts O -4-3-2-1 6 5 4 3 2 + 1 2 3 5 -2+ Evaluate f(3) f(3) = Solve f(x) = 3 x= Question 5

Question 14 6+ 5 4 3 2 -8-2 2 3 4 5 6 + 2 3 4 -5 -6 The graph above is a transformation of the function f(x) = |x| Write an equation for the function graphed above g(x) =