Chapter 6.3, Problem 28E

A mass of 1.25 kg stretches a spring 0.08 mm. The mass is in a medium that exerts a viscous resistance of 45 NN when the mass has a velocity of 6 msms. The viscous resistance is proportional to the speed of the object.Suppose the object is displaced an additional 0.05 mm and released.Find an function to express the object's displacement from the spring's natural position, in mm after tt seconds. Let positive displacements indicate a stretched spring, and use 9.8 ms2ms2 as the acceleration due to gravity.u(t) = 5·10−5(e−3t)sin(349.98t+π2​)mIncorrect  syntax error. Check your variables - you might be using an incorrect one. Submit QuestionQuestion 1

A mass of 1.25 kg stretches a spring 0.08 mm. The mass is in a medium that exerts a viscous resistance of 45 NN when the mass has a velocity of 6 msms. The viscous resistance is proportional to the speed of the object. Suppose the object is displaced an additional 0.05 mm and released. Find an function to express the object's displacement from the spring's natural position, in mm after tt seconds. Let positive displacements indicate a stretched spring, and use 9.8 ms2ms2 as the acceleration due to gravity.

Differentiate. f (t) = 2/t - 3t3