CALCULUS:GRAPHICAL...,AP ED.-W/ACCESS
5th Edition
ISBN: 9780133314564
Author: Finney
Publisher: SAVVAS L
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Use differential to approximate the change in y=x3+x2 as x changes from 1 to 0,95.
A mass of 1.25 kg stretches a spring 0.08 mm. The mass is in a medium that exerts a viscous resistance of 45 NN when the mass has a velocity of 6 msms. The viscous resistance is proportional to the speed of the object.Suppose the object is displaced an additional 0.05 mm and released.Find an function to express the object's displacement from the spring's natural position, in mm after tt seconds. Let positive displacements indicate a stretched spring, and use 9.8 ms2ms2 as the acceleration due to gravity.u(t) = 5·10−5(e−3t)sin(349.98t+π2)mIncorrect syntax error. Check your variables - you might be using an incorrect one.
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A mass of 1.25 kg stretches a spring 0.08 mm. The mass is in a medium that exerts a viscous resistance of 45 NN when the mass has a velocity of 6 msms. The viscous resistance is proportional to the speed of the object.
Suppose the object is displaced an additional 0.05 mm and released.
Find an function to express the object's displacement from the spring's natural position, in mm after tt seconds. Let positive displacements indicate a stretched spring, and use 9.8 ms2ms2 as the acceleration due to gravity.
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