Part (a): Explanation Given: The equation is y = x e − x , y = 0 , x = 2 ; about y -axis. Calculation: Show the equation as below: y = x e − x (1) Plot a graph for the equation y = x e − x using the calculation as follows: Calculate y value using Equation (1). Substitute 0 for x in Equation (1). y = ( 0 ) e − ( 0 ) = 0 Hence, the co-ordinate of ( x , y ) is ( 0 , 0 ) . Calculate y value using Equation (1) Substitute 1 for x in Equation (1). y = ( 1 ) e − ( 1 ) = 0.37 Hence, the co-ordinate of ( x , y ) is ( 1 , 0.37 ) . Calculate y value using Equation (1) Substitute 2 for x in Equation (1). y = ( 2 ) e − ( 2 ) = 0.27 Hence, the co-ordinate of ( x , y ) is ( 2 , 0 Part (b): To determine To evaluate: The integral function.

Single Variable Calculus: Early Transcendentals

8th Edition

ISBN: 9781305270336

Author: James Stewart

Publisher: Cengage Learning

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Chapter 6.3, Problem 21E

Part (a):

To determine

To set up: an integral function for the volume of the solid obtained by rotating the region bounded by the given curve.

Part (b):

To determine

To evaluate: The integral function.

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Chapter 6.3, Problem 20E

Chapter 6.3, Problem 22E

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Chapter 6 Solutions

Single Variable Calculus: Early Transcendentals

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To set up: an integral function for the volume of the solid obtained by rotating the region bounded by the given curve.

Solution Summary: The author describes the integral function for the volume of the solid obtained by rotating the region bounded by the given curve.

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To set up: an integral function for the volume of the solid obtained by rotating the region bounded by the given curve.

To evaluate: The integral function.

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Chapter 6 Solutions