Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 63, Problem 12A
To determine

To compare:

The weight of the larger and smaller piece of a right circular cone.

Expert Solution & Answer
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Answer to Problem 12A

  V2=4V1

Explanation of Solution

Given:

Height h = 6in.

Base diameter of smaller piece D1 = 2in.

Base diameter of larger piece D2 = 4in.

Concept used:

The volume of a right circular cone is

  V =13ABh

Where, h = height, and AB = Base area.

Calculation:

The base area is Ab=πr2

Now, the base area of smaller cone is

  Ab1=227×( D 1 2)2[r=D2]Ab1=227×( 2 2)2Ab1=227in.2

Now, the base area of larger cone is

  Ab2=227×( D 2 2)2[r=D2]Ab2=227×( 4 2)2Ab2=227×(2)2Ab2=887in.2

Thus, volume of smaller cone is

  V1 =13×227×6or,V1 =227×2V1 = 447in.3

And, the volume of larger cone is

  V2 =13×887×6or,V2 =887×2V2 = 447×4in.3V2 =4V1

Conclusion:

Hence, volume of cone of larger diameter is 4 times heavier than the cone of smaller diameter.

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