Chapter 6.2, Problem 50E

The kinetic energy E of an object varies jointly with the object’s mass m and the square of the object’s velocity v . An object with a mass of 50 kilograms traveling at 16 meters per second has a kinetic energy of 6400 joules. What is the kinetic energy of an object with a mass of 70 kilograms traveling at 20 meters per second?

Find the intensity of light at a depth of 12 meter if I0=14 and k=0.7. Round to two decimals.

A carbide milling cutter is used for machining a 27.25-inch length of stainless steel. The cutting time is 12.35 minutes, the cutting speed is 240 feet per minute, and the feed is 0.01 inches per revolution. What is the diameter of the carbide milling cutter? Round the answer to 2 decimal places.

Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places unless otherwise specified. A vessel in the shape of a right circular cone has a capacity of 0.690 liter. The base diameter is 12.30 centimeters. What is the height of the vessel? One liter contains 1000 cubic centimeters.

All dimensions are in inches. Round the answers to 3 decimal places. a. If y = 2.8000" find x. b If y = 3.000", find x.

Cast iron 10 cm in diameter is turned in a lathe at 350 rpm. Each length of cut is 65 cm and eight cuts are required.A carbide tool is fed into the work at 0.0425 cm = 0.425 mm per revolution. Use the formula TLFN to find thetotal cutting time. Round the answerto 1 decimal place.

Find the intensities of earthquakes whose magnitudes are aR=6.0andbR=7.9.

A piece in the shape of a pyramid with a regular octagon (eight sided) base is machined from a solid block of bronze. Each side of the octagon base is 9.36 inches long. The height of the piece is 7.08 inches. The octagon base area 4.829, where s is the length of a side of the octagon. a. Determine the volume of the piece. Round the answer to the nearest cubic inch. b. Determine the weight of the piece. Round the answer to the nearest pound. Note: One cubic foot of the bronze used weighs 547.9 pounds per cubic foot.

Tsunami Waves and BreakwatersThis is a continuation of Exercise 16. Breakwaters affect wave height by reducing energy. See Figure 5.30. If a tsunami wave of height H in a channel of width W encounters a breakwater that narrows the channel to a width w, then the height h of the wave beyond the breakwater is given by h=HR0.5, where R is the width ratio R=w/W. a. Suppose a wave of height 8 feet in a channel of width 5000feet encounters a breakwater that narrows the channel to 3000feet. What is the height of the wave beyond the breakwater? b. If a channel width is cut in half by a breakwater, what is the effect on wave height? 16. Height of Tsunami WavesWhen waves generated by tsunamis approach shore, the height of the waves generally increases. Understanding the factors that contribute to this increase can aid in controlling potential damage to areas at risk. Greens law tells how water depth affects the height of a tsunami wave. If a tsunami wave has height H at an ocean depth D, and the wave travels to a location with water depth d, then the new height h of the wave is given by h=HR0.25, where R is the water depth ratio given by R=D/d. a. Calculate the height of a tsunami wave in water 25feet deep if its height is 3feet at its point of origin in water 15,000feet deep. b. If water depth decreases by half, the depth ratio R is doubled. How is the height of the tsunami wave affected?