Student Solutions Manual For Zill's A First Course In Differential Equations With Modeling Applications, 11th
11th Edition
ISBN: 9781305965737
Author: Dennis G. Zill
Publisher: Brooks Cole
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Chapter 6.2, Problem 2E
In Problems 1 and 2 without actually solving the given differential equation, find the minimum radius of convergence of power series solutions about the ordinary point x = 0. About the ordinary point x = 1.
2. (x2 − 2x + 10)y″ + xy′ − 4y = 0
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Chapter 6 Solutions
Student Solutions Manual For Zill's A First Course In Differential Equations With Modeling Applications, 11th
Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 1–10 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 1–10 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...Ch. 6.1 - In Problems 110 find the interval and radius of...
Ch. 6.1 - In Problems 1116 use an appropriate series in (2)...Ch. 6.1 - In Problems 1116 use an appropriate series in (2)...Ch. 6.1 - In Problems 1116 use an appropriate series in (2)...Ch. 6.1 - In Problems 11–16 use an appropriate series in (2)...Ch. 6.1 - In Problems 1116 use an appropriate series in (2)...Ch. 6.1 - In Problems 1116 use an appropriate series in (2)...Ch. 6.1 - In Problems 17 and 18 use an appropriate series in...Ch. 6.1 - In Problems 17 and 18 use an appropriate series in...Ch. 6.1 - In Problems 19 and 20 the given function is...Ch. 6.1 - In Problems 19 and 20 the given function is...Ch. 6.1 - In Problems 21 and 22 the given function is...Ch. 6.1 - In Problems 21 and 22 the given function is...Ch. 6.1 - In Problems 23 and 24 use a substitution to shift...Ch. 6.1 - In Problems 23 and 24 use a substitution to shift...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 2530 proceed as in Example 3 to...Ch. 6.1 - In Problems 3134 verify by direct substitution...Ch. 6.1 - In Problems 3134 verify by direct substitution...Ch. 6.1 - In Problems 3134 verify by direct substitution...Ch. 6.1 - In Problems 3134 verify by direct substitution...Ch. 6.1 - In Problems 35–38 proceed as in Example 4 and find...Ch. 6.1 - In Problems 3538 proceed as in Example 4 and find...Ch. 6.1 - In Problems 3538 proceed as in Example 4 and find...Ch. 6.1 - Prob. 38ECh. 6.1 - Prob. 39ECh. 6.1 - Prob. 40ECh. 6.2 - In Problems 1 and 2 without actually solving the...Ch. 6.2 - In Problems 1 and 2 without actually solving the...Ch. 6.2 - In Problems 3–6 find two power series solutions of...Ch. 6.2 - In Problems 36 find two power series solutions of...Ch. 6.2 - In Problems 3–6 find two power series solutions of...Ch. 6.2 - In Problems 36 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 7–18 find two power series solutions...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 718 find two power series solutions of...Ch. 6.2 - In Problems 1922 use the power series method to...Ch. 6.2 - In Problems 1922 use the power series method to...Ch. 6.2 - In Problems 1922 use the power series method to...Ch. 6.2 - In Problems 19–22 use the power series method to...Ch. 6.2 - In Problems 23 and 24 use the procedure in Example...Ch. 6.2 - In Problems 23 and 24 use the procedure in Example...Ch. 6.2 - Without actually solving the differential equation...Ch. 6.2 - How can the power series method be used to solve...Ch. 6.2 - Is x = 0 an ordinary or a singular point of the...Ch. 6.2 - Prob. 28ECh. 6.3 - In Problems 110 determine the singular points of...Ch. 6.3 - Prob. 2ECh. 6.3 - In Problems 110 determine the singular points of...Ch. 6.3 - In Problems 110 determine the singular points of...Ch. 6.3 - In Problems 110 determine the singular points of...Ch. 6.3 - Prob. 6ECh. 6.3 - Prob. 7ECh. 6.3 - Prob. 8ECh. 6.3 - Prob. 9ECh. 6.3 - Prob. 10ECh. 6.3 - Prob. 11ECh. 6.3 - Prob. 12ECh. 6.3 - In Problems 13 and 14, x = 0 is a regular singular...Ch. 6.3 - Prob. 14ECh. 6.3 - Prob. 15ECh. 6.3 - Prob. 16ECh. 6.3 - Prob. 17ECh. 6.3 - Prob. 18ECh. 6.3 - In Problems 1524, x = 0 is a regular singular...Ch. 6.3 - Prob. 20ECh. 6.3 - Prob. 21ECh. 6.3 - Prob. 22ECh. 6.3 - Prob. 23ECh. 6.3 - Prob. 24ECh. 6.3 - Prob. 25ECh. 6.3 - In Problems 2530, x = 0 is a regular singular...Ch. 6.3 - In Problems 2530, x = 0 is a regular singular...Ch. 6.3 - Prob. 28ECh. 6.3 - Prob. 29ECh. 6.3 - Prob. 30ECh. 6.3 - Prob. 31ECh. 6.3 - Prob. 32ECh. 6.3 - (a) The differential equation x4y + y = 0 has an...Ch. 6.3 - Prob. 35ECh. 6.3 - Prob. 36ECh. 6.3 - Prob. 37ECh. 6.4 - Prob. 1ECh. 6.4 - Prob. 2ECh. 6.4 - Prob. 3ECh. 6.4 - Bessels Equation In Problems 16 use (1) to find...Ch. 6.4 - Prob. 5ECh. 6.4 - Prob. 6ECh. 6.4 - Prob. 7ECh. 6.4 - Prob. 8ECh. 6.4 - Prob. 9ECh. 6.4 - Prob. 10ECh. 6.4 - In Problems 11 and 12 use the indicated change of...Ch. 6.4 - Prob. 12ECh. 6.4 - Prob. 13ECh. 6.4 - Prob. 14ECh. 6.4 - Prob. 15ECh. 6.4 - Prob. 16ECh. 6.4 - Prob. 17ECh. 6.4 - Prob. 18ECh. 6.4 - Prob. 19ECh. 6.4 - Prob. 20ECh. 6.4 - Prob. 21ECh. 6.4 - Prob. 22ECh. 6.4 - Prob. 23ECh. 6.4 - Prob. 24ECh. 6.4 - Prob. 25ECh. 6.4 - Prob. 26ECh. 6.4 - Prob. 27ECh. 6.4 - Prob. 28ECh. 6.4 - Prob. 29ECh. 6.4 - Prob. 30ECh. 6.4 - Prob. 31ECh. 6.4 - Use the recurrence relation in Problem 28 along...Ch. 6.4 - Prob. 33ECh. 6.4 - Prob. 34ECh. 6.4 - Use the change of variables s=2kmet/2 to show that...Ch. 6.4 - Show that y=x1/2w(23x3/2) is a solution of the...Ch. 6.4 - Prob. 37ECh. 6.4 - Prob. 38ECh. 6.4 - Prob. 39ECh. 6.4 - (a) Use the explicit solutions y1(x) and y2(x) of...Ch. 6.4 - Prob. 47ECh. 6.4 - Show that the differential equation...Ch. 6.4 - Find the first three positive values of for which...Ch. 6.4 - Prob. 53ECh. 6.4 - Prob. 54ECh. 6.4 - Prob. 55ECh. 6.4 - Prob. 56ECh. 6 - In Problems 1 and 2 answer true or false without...Ch. 6 - Prob. 2RECh. 6 - Both power series solutions of y + ln(x + 1)y + y...Ch. 6 - x = 0 is an ordinary point of a certain linear...Ch. 6 - Suppose the power series k0ck(x4)k is known to...Ch. 6 - Prob. 6RECh. 6 - Prob. 7RECh. 6 - Prob. 8RECh. 6 - Prob. 9RECh. 6 - Prob. 10RECh. 6 - Prob. 11RECh. 6 - Prob. 12RECh. 6 - Prob. 13RECh. 6 - Prob. 14RECh. 6 - Prob. 15RECh. 6 - Prob. 16RECh. 6 - Without actually solving the differential equation...Ch. 6 - Prob. 18RECh. 6 - Prob. 19RECh. 6 - Prob. 20RECh. 6 - Prob. 21RECh. 6 - The first-order differential equation dy/dx = x2 +...Ch. 6 - Prob. 23RECh. 6 - Prob. 24RECh. 6 - Prob. 25RECh. 6 - Prob. 26RECh. 6 - Cooling Fin A cooling fin is an outward projection...Ch. 6 - Solve the differential equation in Problem 27 if...
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- By considering appropriate series expansions, e². e²²/2. e²³/3. .... = = 1 + x + x² + · ... when |x| < 1. By expanding each individual exponential term on the left-hand side the coefficient of x- 19 has the form and multiplying out, 1/19!1/19+r/s, where 19 does not divide s. Deduce that 18! 1 (mod 19).arrow_forwardProof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.arrow_forwardBy considering appropriate series expansions, ex · ex²/2 . ¸²³/³ . . .. = = 1 + x + x² +…… when |x| < 1. By expanding each individual exponential term on the left-hand side and multiplying out, show that the coefficient of x 19 has the form 1/19!+1/19+r/s, where 19 does not divide s.arrow_forward
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