Explanation Given: The expression, 2 x 2 − 3 x y − 2 y 2 3 x 2 − 4 x y + y 2 ⋅ 3 x 2 − 2 x y − y 2 x 2 + x y − 6 y 2 . Calculation: Factorize all numerators and denominators completely. 2 x 2 − 3 x y − 2 y 2 3 x 2 − 4 x y + y 2 ⋅ 3 x 2 − 2 x y − y 2 x 2 + x y − 6 y 2 = ( y + 2 x ) ( x − 2 y ) ( y − 3 x ) ( y − x ) ⋅ ( y + 3 x ) ( x − y ) ( 3 y + x ) ( x − 2 y ) Divide numerators and denominators by common factors ( y − x ) and ( x − 2 y ) . 2 x 2 − 3 x y − 2 y 2 3 x 2 − 4 x y + y 2 ⋅ 3 x 2 − 2 x y − y 2 x 2 + x y − 6 y 2 = ( y + 2 x ) ( x − 2 y

Intermediate Algebra for College Students (7th Edition)

7th Edition

ISBN: 9780134178943

Author: Robert F. Blitzer

Publisher: PEARSON

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Chapter 6.1, Problem 68E

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To calculate: The product of the expression, 2x2−3xy−2y23x2−4xy+y2⋅3x2−2xy−y2x2+xy−6y2.

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Chapter 6.1, Problem 67E

Chapter 6.1, Problem 69E

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Chapter 6 Solutions

Intermediate Algebra for College Students (7th Edition)

Ch. 6.1 - Check Point 1 Use the rational function in...Ch. 6.1 - Check Point 2 Find the domain of f if...Ch. 6.1 - Prob. 3CP Ch. 6.1 - Prob. 4CP Ch. 6.1 - Prob. 5CP Ch. 6.1 - Prob. 6CP Ch. 6.1 - Prob. 7CP Ch. 6.1 - Prob. 1CVC Ch. 6.1 - Prob. 2CVC Ch. 6.1 - Prob. 3CVC

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The product of the expression, 2 x 2 − 3 x y − 2 y 2 3 x 2 − 4 x y + y 2 ⋅ 3 x 2 − 2 x y − y 2 x 2 + x y − 6 y 2 .

Solution Summary: The author explains how to calculate the product of the given expression, -y2+5xy+6x2.

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To calculate: The product of the expression, 2x2−3xy−2y23x2−4xy+y2⋅3x2−2xy−y2x2+xy−6y2.

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Chapter 6 Solutions