Explanation The figure 1 represents the free body of the truss. Write the expression for the sum of all the forces acting along x direction. ∑ F x = 0 A x = 0 From the symmetry of loading, A y = I = 1 2 total load A y = I = 6 kN Considering the Joint A , This joint is subjected to only two unknown forces, the forces exerted by A B and those by A C . Use a force triangle to determine F A B and F A C . Figure 1 represents the force triangle. the member A B pushes on the joint so A B is in compression and the member A C pulls the joint so A C is in Tension. Write the expression for the forces in proportion form from the force triangle. F A B 9.849 = F A C 9 = 5 kN 4 (I) Here, F A B is the force acting along A B , F A C is the force acting along A C . Consider the joint B This joint is subjected to only two unknown force, the force exerted by B D and those by B C . Use a force triangle to determine F B C and F B D . Figure 3 represents the force triangle. the member B D and B C pushes the joint so B D and B C are in Compression. Write the expression for the sum of all forces acting along x direction. 9 9.849 ( F A B + F B D + F D C ) = 0 (II) Write the expression for the sum of all forces acting along y direction. 4 9.849 ( 12.31 kN+ F B D − F B C ) − 2 kN = 0 (III) Considering the joint C , This joint is subjected to two unknown forces, the forces exerted by C E and those by C G and. Use a force polygon to determine F C E and F C G .in the Figure 5. the member C E and C G pulls on the joint so C D and C G are in Tension. Considering the joint D , This joint is subjected to two unknown forces, the forces exerted by C D and those by D E and. Use a force polygon to determine F C D and F D E .in the Figure 3. the member C D and D E pushes on the joint so C D and D E are in compression. Write the expression for the sum of all forces acting along y direction. 4 5 F C E − 4 9.849 F B C − F C D = 0 (IV) Write the expression for the sum of all forces acting along x direction. F C G + 3 5 ( 3.75 kN ) + 9 9.849 ( F B C ) − F C D = 0 (V) Conclusion: For the joint A , Solve equation I to find F A B and F A C . F A B 9.849 = F A C 9 = 5 kN 4 F A B = 12.31 kN F A C = 11.25 kN For the joint B , Substitute 12

12th Edition

ISBN: 9781260912814

Author: BEER

Publisher: MCG

See similar textbooks

Concept explainers

Plane Trusses

It is defined as, two or more elements like beams or any two or more force members, which when assembled together, behaves like a complete structure or as a single structure. They generally consist of two force member which means any component structure …

Equilibrium Equations

If a body is said to be at rest or moving with a uniform velocity, the body is in equilibrium condition. This means that all the forces are balanced in the body. It can be understood with the help of Newton's first law of motion which states that the res…

Force Systems

When a body comes in interaction with other bodies, they exert various forces on each other. Any system is under the influence of some kind of force. For example, laptop kept on table exerts force on the table and table exerts equal force on it, hence th…

Videos

Question

Chapter 6.1, Problem 6.14P

To determine

Determine the force in each member of the truss and state whether each member is in tension or compression.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 6.1, Problem 6.13P

Chapter 6.1, Problem 6.15P

Students have asked these similar questions

1 Revolute four-bar mechanism, AB=60mm, BC=130mm, CD=140mm, AD=200mm,

CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. The roof truss shown carries roof loads, where P = 10 kN. The truss is consisting of circular arcs top andbottom chords with radii R + h and R, respectively.Given: h = 1.2 m, R = 10 m, s = 2 m.Allowable member stresses:Tension = 250 MPaCompression = 180 MPa1. If member KL has square section, determine the minimum dimension (mm).2. If member KL has circular section, determine the minimum diameter (mm).3. If member GH has circular section, determine the minimum diameter (mm).ANSWERS: (1) 31.73 mm; (2) 35.81 mm; (3) 18.49 mm

CORRECT AND DETAILED HANDWRITTEN SOLUTION WITH FBD ONLY. I WILL UPVOTE THANK YOU. CORRECT ANSWER IS ALREADY PROVIDED. The cantilevered spandrel beam shown whose depth tapers from d1 to d2, has a constant width of 120mm. It carries a triangularly distributed end reaction.Given: d1 = 600 mm, d2 = 120 mm, L = 1 m, w = 100 kN/m1. Calculate the maximum flexural stress at the support, in kN-m.2. Determine the distance (m), from the free end, of the section with maximum flexural stress.3. Determine the maximum flexural stress in the beam, in MPa.ANSWERS: (1) 4.630 MPa; (2) 905.8688 m; (3) 4.65 MPa

Chapter 6 Solutions

VECTOR MECHANICS FOR ENGINEERS: STATICS

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Determine the force in each member of the truss and state whether each member is in tension or compression.

Solution Summary: The author determines the force in each member of the truss and states whether each is in tension or compression.

Concept explainers

Videos

Determine the force in each member of the truss and state whether each member is in tension or compression.

Want to see the full answer?

Chapter 6 Solutions