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Chapter 6 Solutions
EBK LINEAR ALGEBRA AND ITS APPLICATIONS
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- In simplest terms, Sketch the graph of the parabola. Then, determine its equation. opens downward, vertex is (- 4, 7), passes through point (0, - 39)arrow_forwardIn simplest way, For each quadratic relation, find the zeros and the maximum or minimum. a) y = x 2 + 16 x + 39 b) y = 5 x2 - 50 x - 120arrow_forwardIn simplest terms and step by step Write each quadratic relation in standard form, then fi nd the zeros. y = - 4( x + 6)2 + 36arrow_forward
- In simplest terms and step by step For each quadratic relation, find the zeros and the maximum or minimum. 1) y = - 2 x2 - 28 x + 64 2) y = 6 x2 + 36 x - 42arrow_forwardWrite each relation in standard form a)y = 5(x + 10)2 + 7 b)y = 9(x - 8)2 - 4arrow_forwardIn simplest form and step by step Write the quadratic relation in standard form, then fi nd the zeros. y = 3(x - 1)2 - 147arrow_forward
- Step by step instructions The path of a soccer ball can be modelled by the relation h = - 0.1 d 2 + 0.5 d + 0.6, where h is the ball’s height and d is the horizontal distance from the kicker. a) Find the zeros of the relation.arrow_forwardIn simplest terms and step by step how do you find the zeros of y = 6x2 + 24x - 192arrow_forwardStep by step Find the zeros of each quadratic relation. a) y = x2 - 16xarrow_forward
- In simplest step by step terms, how do you find the zeros of y = x2 - 16arrow_forwardIn simplest terms, Describe the shape and position of the parabola relative to the graph of y = x 2 y = - 80( x + 9) 2 + 10.8arrow_forwardas a Identify each equation Parabola, circle, ellipse perbola without completio the square. x²-6x-14 y = 33-y² 14y ofarrow_forward
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