Explanation Given Information: The provided inequalities are 20 x + 10 y ≤ 100 , 10 x + 20 y ≤ 5 , 10 x + 10 y ≤ 60 , x ≥ 0 and y ≥ 0 . Graph: Consider the provided inequalities are, 20 x + 10 y ≤ 100 , 10 x + 20 y ≤ 5 , 10 x + 10 y ≤ 60 , x ≥ 0 and y ≥ 0 , Consider the inequality 20 x + 10 y ≤ 100 Assume the equation as, 20 x + 10 y = 100 Now, substitute the values of x in order to get the corresponding values of y and sketch the graph of the line. For x = 0 20 ( 0 ) + 10 y = 100 10 y = 100 y = 10 Therefore, the point is ( 0 , 10 ) For x = 1 20 ( 1 ) + 10 y = 100 10 y = 80 y = 8 Therefore, the point is ( 1 , 8 ) For x = 5 20 ( 5 ) + 10 y = 100 10 y = 0 y = 0 Therefore, the point is ( 5 , 0 ) The points for the equation 20 x + 10 y = 100 are as follows: x y ( x , y ) 0 10 ( 0 , 10 ) 5 0 ( 5 , 0 ) 1 8 ( 1 , 8 ) The graph of the inequality is as follows: Hence, the boundary points for the equation are ( 5 , 0 ) and ( 0 , 10 ) Consider the inequality 10 x + 20 y ≤ 100 Assume the equation as, 10 x + 20 y = 100 Now, substitute the values of x in order to get the corresponding values of y and sketch the graph of the line. For x = 0 10 ( 0 ) + 20 y = 100 20 y = 100 y = 5 Therefore, the point is ( 0 , 5 ) For x = 1 10 ( 1 ) + 20 y = 100 20 y = 90 y = 9 2 Therefore, the point is ( 1 , 9 2 ) For x = 10 10 ( 10 ) + 20 y = 100 20 y = 0 y = 0 Therefore, the point is ( 10 , 0 ) The points for the equation 10 x + 20 y = 100 are as follows: x y ( x , y ) 0 5 ( 0 , 5 ) 10 0 ( 10 , 0 ) 1 9 2 ( 1 , 9 2 ) The graph of the inequality is as follows: Hence, the boundary points for the equation are ( 10 , 0 ) and ( 0 , 5 ) Consider the inequality 10 x + 10 y ≤ 60 Assume the equation as, 10 x + 10 y = 60 Now, substitute the values of x in order to get the corresponding values of y and sketch the graph of the line. For x = 0 10 ( 0 ) + 10 y = 60 10 y = 60 y = 6 Therefore, the point is ( 0 , 6 ) . For x = 1 10 ( 1 ) + 10 y = 60 10 y = 50 y = 5 Therefore, the point is ( 1 , 5 ) For x = 6 10 ( 6 ) + 10 y = 60 y = 0 Therefore, the point is ( 6 , 0 ) The points for the equation 10 x + 10 y = 60 are as follows: x y ( x , y ) 0 6 ( 0 , 6 ) 6 0 ( 6 , 0 ) 1 5 ( 1 , 5 ) The graph of the inequality is as follows:

Finite Mathematics and Applied Calculus (MindTap Course List)

7th Edition

ISBN: 9781337274203

Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Chapter 6.1, Problem 19E

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To graph: The inequalities 20x+10y≤100, 10x+20y≤5, 10x+10y≤60, x≥0 and y≥0 and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

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Chapter 6.1, Problem 18E

Chapter 6.1, Problem 20E

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Chapter 6 Solutions

Finite Mathematics and Applied Calculus (MindTap Course List)

Ch. 6.1 - In Exercises 1-26, sketch the region that...Ch. 6.1 - In Exercises 1-26, sketch the region that...Ch. 6.1 - Prob. 3E Ch. 6.1 - Prob. 4E Ch. 6.1 - Prob. 5E Ch. 6.1 - Prob. 6E Ch. 6.1 - Prob. 7E Ch. 6.1 - In Exercises 1-26, sketch the region that...Ch. 6.1 - Prob. 9E Ch. 6.1 - Prob. 10E

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To graph: The inequalities 20 x + 10 y ≤ 100 , 10 x + 20 y ≤ 5 , 10 x + 10 y ≤ 60 , x ≥ 0 and y ≥ 0 and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

Solution Summary: The author explains how to graph the inequalities of 20x+10yle 100, x, and y.

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To graph: The inequalities 20x+10y≤100, 10x+20y≤5, 10x+10y≤60, x≥0 and y≥0 and also check whether the region of the inequalities are bounded or unbounded and find the coordinates of all the corner points if possible.

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Chapter 6 Solutions