EBK STATISTICS FOR THE BEHAVIORAL SCIEN
3rd Edition
ISBN: 9781506386249
Author: PRIVITERA
Publisher: VST
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Chapter 6, Problem 9FP
To determine
Find the type of distribution which binomial distribution approximates.
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Compute the relative risk of falling for the two groups (did not stop walking vs. did stop). State/interpret your result verbally.
Microsoft Excel include formulas
Question 1
The data shown in Table 1 are and R values for 24 samples of size n = 5 taken from a process producing
bearings. The measurements are made on the inside diameter of the bearing, with only the last three decimals
recorded (i.e., 34.5 should be 0.50345).
Table 1: Bearing Diameter Data
Sample Number
I
R
Sample Number
I R
1
34.5
3
13
35.4
8
2
34.2
4
14
34.0
6
3
31.6
4
15
37.1
5
4
31.5
4
16
34.9
7
5
35.0
5
17
33.5
4
6
34.1
6
18
31.7
3
7
32.6
4
19
34.0
8
8
33.8
3
20
35.1
9
34.8
7
21
33.7
2
10
33.6
8
22
32.8
1
11
31.9
3
23
33.5
3
12
38.6 9
24
34.2
2
(a) Set up and R charts on this process. Does the process seem to be in statistical control? If necessary,
revise the trial control limits. [15 pts]
(b) If specifications on this diameter are 0.5030±0.0010, find the percentage of nonconforming bearings pro-
duced by this process. Assume that diameter is normally distributed. [10 pts]
1
Chapter 6 Solutions
EBK STATISTICS FOR THE BEHAVIORAL SCIEN
Ch. 6.3 - Prob. 1.1LCCh. 6.3 - Prob. 1.2LCCh. 6.3 - Prob. 1.3LCCh. 6.3 - Prob. 1.4LCCh. 6.5 - Prob. 2.1LCCh. 6.5 - Prob. 2.2LCCh. 6.5 - Prob. 2.3LCCh. 6.6 - Prob. 3.1LCCh. 6.6 - Prob. 3.2LCCh. 6.6 - Prob. 3.3LC
Ch. 6.6 - Prob. 3.4LCCh. 6.7 - Prob. 4.1LCCh. 6.7 - Prob. 4.2LCCh. 6.7 - Prob. 4.3LCCh. 6.9 - Prob. 5.1LCCh. 6.9 - Prob. 5.2LCCh. 6.9 - Prob. 5.3LCCh. 6.10 - Prob. 6.1LCCh. 6.10 - Prob. 6.2LCCh. 6 - Prob. 1FPCh. 6 - Prob. 2FPCh. 6 - Prob. 3FPCh. 6 - Prob. 4FPCh. 6 - Prob. 5FPCh. 6 - Prob. 6FPCh. 6 - Prob. 7FPCh. 6 - Prob. 8FPCh. 6 - Prob. 9FPCh. 6 - Prob. 10FPCh. 6 - Prob. 11CAPCh. 6 - Prob. 12CAPCh. 6 - Prob. 13CAPCh. 6 - Prob. 14CAPCh. 6 - Prob. 15CAPCh. 6 - Prob. 16CAPCh. 6 - Prob. 17CAPCh. 6 - Prob. 18CAPCh. 6 - Prob. 19CAPCh. 6 - Prob. 20CAPCh. 6 - Prob. 21CAPCh. 6 - Prob. 22CAPCh. 6 - Prob. 23CAPCh. 6 - Prob. 24CAPCh. 6 - Prob. 25CAPCh. 6 - Prob. 26PRCh. 6 - Prob. 27PRCh. 6 - Prob. 28PRCh. 6 - Prob. 29PRCh. 6 - Prob. 30PRCh. 6 - Prob. 31PRCh. 6 - Prob. 32PR
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- 4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether there is an association between the behavior of the elderly person (did not stop to talk, did stop to talk) and their likelihood of falling. Below, please state your null and alternative hypotheses, calculate your expected values and write them in the table, compute the test statistic, test the null by comparing your test statistic to the critical value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and provide your conclusions in written form. Make sure to show your work. Did not stop walking to talk Stopped walking to talk Suffered a fall 12 11 Totals 23 Did not suffer a fall | 2 Totals 35 37 14 46 60 Tarrow_forwardQuestion 2 Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2. Table 2: Strength Data for Question 2 Sample Number x1 x2 23 x4 x5 R 1 83.0 2 88.6 78.3 78.8 3 85.7 75.8 84.3 81.2 78.7 75.7 77.0 71.0 84.2 81.0 79.1 7.3 80.2 17.6 75.2 80.4 10.4 4 80.8 74.4 82.5 74.1 75.7 77.5 8.4 5 83.4 78.4 82.6 78.2 78.9 80.3 5.2 File Preview 6 75.3 79.9 87.3 89.7 81.8 82.8 14.5 7 74.5 78.0 80.8 73.4 79.7 77.3 7.4 8 79.2 84.4 81.5 86.0 74.5 81.1 11.4 9 80.5 86.2 76.2 64.1 80.2 81.4 9.9 10 75.7 75.2 71.1 82.1 74.3 75.7 10.9 11 80.0 81.5 78.4 73.8 78.1 78.4 7.7 12 80.6 81.8 79.3 73.8 81.7 79.4 8.0 13 82.7 81.3 79.1 82.0 79.5 80.9 3.6 14 79.2 74.9 78.6 77.7 75.3 77.1 4.3 15 85.5 82.1 82.8 73.4 71.7 79.1 13.8 16 78.8 79.6 80.2 79.1 80.8 79.7 2.0 17 82.1 78.2 18 84.5 76.9 75.5 83.5 81.2 19 79.0 77.8 20 84.5 73.1 78.2 82.1 79.2 81.1 7.6 81.2 84.4 81.6 80.8…arrow_forwardName: Lab Time: Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26 Contingency Analysis (Ch. 9) In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop) were more likely to suffer a fall in the next six months. I have tabulated the data below. Answer the questions below. Please show your calculations on this or a separate sheet. Did not stop walking to talk Stopped walking to talk Totals Suffered a fall Did not suffer a fall Totals 12 11 23 2 35 37 14 14 46 60 Quiz 7: 1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those who did not stop walking vs. those who did stop walking. Interpret your result verbally.arrow_forward
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