Chapter 6, Problem 86E

(a)

To determine

Calculate the probability ofMarketing A.

Explanation of Solution

The probability of Marketing Acan be calculated as follows:

$\begin{array}{c}\text{P}\left(\text{marketing A}\right)=0.053+0.237\\ =0.290\end{array}$

Thus, the value of probability is 0.290.

(b)

To determine

Calculate the probability of Marketing A and not Statistics A.

Explanation of Solution

The probability of Marketing A and statistics not Acan be calculated as follows:

$\begin{array}{c}\text{P}\left(\text{Marketing A}|\text{Statistics not A}\right)=\frac{\text{P}\left(\text{Marketing and statistics not A}\right)}{\text{P}\left(\text{Statistics not A}\right)}\\ =\frac{0.237}{0.237+0.580}\\ =\frac{0.237}{0.817}\\ =0.290\end{array}$

Thus, the value of probability is 0.290.

(c)

To determine

Explain whether a grade in Marketing A and statistics are independent ornot.

Explanation of Solution

Yes, it is because from the above calculation the probability value of Marketing A and not Statistics A are equal.