Explanation Given: Angle made by hill with horizontal = 6.0 ° Steady speed of cyclist in downward motion = 4 .0 m/s Total mass of bicycle plus rider = 75 kg Formula used: P = W t = F V cos θ W : Work t : time F: force V: speed θ : angle between force and velocity. Newton’s second law ∑ F x = m a x ∑ F x = m a y Calculation: When cyclist moves down ward with steady speed. N : normal reaction by hill on bicycle Mg : weight of cyclist plus rider. F : friction force acting upwards along the hill. ∑ F x = 0 Considering x -axis along the inclined plane. m g sin θ − f = 0 f = m g sin θ → ( 1 ) When cyclist moves up ward with steady speed ( 4 m / s ) Friction force acts down ward, because cycle moves upward. N : normal reaction by hill on bicycle Mg : weight of cyclist plus rider F : friction force F p : pull on bicycle in upward direction Normal, and contact surface is same so friction on the cyclist remain same only direction will be reversed

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ISBN: 9780137453276

Author: GIANCOLI

Publisher: SAVVAS L

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Chapter 6, Problem 71P

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The cyclist power output to climb the same hill at the same speed.

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Chapter 6, Problem 70P

Chapter 6, Problem 72GP

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Chapter 6 Solutions

EP PHYSICS: PRIN.APP.AP-MOD.MASTERING

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