Chapter 6, Problem 6G.9E

(a)

Interpretation Introduction

Interpretation:

The $pH$ of the solution that results from mixing $30.0mLof0.050MHCN\left(aq\right)and70.0mLof0.030MNaCN\left(aq\right)$ has to be calculated.

Concept Introduction:

Henderson – Hasselbalch equation:

The $pH$ of a buffer can be easily calculated by using Henderson – Hasselbalch equation as given below.

  $\begin{array}{c}pH=p{K}_a+\log \frac{{\left[base\right]}_{initial}}{{\left[acid\right]}_{initial}}\\ \\ =p{K}_a+\log \left(\frac{molesofbase}{molesofacid}\right)\end{array}$

(b)

Interpretation Introduction

Interpretation:

The $pH$ of the solution that results from mixing $40.0mLof0.030MHCN\left(aq\right)and60.0mLof0.050MNaCN\left(aq\right)$ has to be calculated.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

The $pH$ of the solution that results from mixing $25.0mLof0.105MHCN\left(aq\right)and25.0mLof0.105MNaCN\left(aq\right)$ has to be calculated.

Concept Introduction:

Refer to part (a).