(a)
Interpretation: The value of
Concept introduction: The Gibbs free energy of the reaction is the key factor of the identification of the direction of spontaneity of the reaction. For the reaction to be spontaneous, the Gibbs free energy of the reaction must be negative.
(b)
Interpretation: The partial pressure of
Concept introduction: The equilibrium constant for a reaction is abbreviated as
(c)
Interpretation: Considering the vapour pressure of iodine at
Concept introduction: The equilibrium constant for a reaction is abbreviated as

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Chapter 6 Solutions
PHYSICAL CHEMISTRY. VOL.1+2 (LL)(11TH)
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- Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic. ZI NH Explanation Check O aromatic O antiaromatic O nonaromatic O aromatic O antiaromatic H O nonaromatic O aromatic O antiaromatic O nonaromatic ×arrow_forwardPart I. Draw the stepwise reaction mechanism of each product (a, b, c, d, e, f) HO HO OH НОН,С HO OH Sucrose HO CH₂OH H N N HO -H H -OH KMnO4, Heat H OH CH₂OH (d) Phenyl Osatriazole OH НОН,С HO HO + Glacial HOAC HO- HO CH₂OH OH HO Fructose (a) Glucose OH (b) H₂N HN (c) CuSO4-5H2O, ethanol H N N N HO ·H H OH H OH N CH₂OH OH (f) Phenyl Osazone H (e) Carboxy phenyl osatriazole Figure 2.1. Reaction Scheme for the Total Synthesis of Fine Chemicalsarrow_forwardWhich molecule is the most stable? Please explain.arrow_forward
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