Chapter 6, Problem 6.94P

(a)

Interpretation Introduction

Interpretation:

The energy in $\text{kJ}$ that is released by combustion of $20.4\text{ gal}$ of isooctane to gases is to be determined.

Concept introduction:

Heat $\left(q\right)$ is the energy transferred as a consequence of the difference of the temperature between the system and surrounding.

The heat released by the system is negative and the heat taken by the system is positive.

The amount of heat released by the system is equal to the amount of heat absorbed by the surrounding.

The conversion factor to convert $\text{gal}$ into $\text{qt}$ is:

$\text{1}\text{gal}=4\text{qt}$

The conversion factor to convert $\text{L}$ into $\text{qt}$ is:

$\text{1}\text{L}=1.057\text{qt}$

(b)

Interpretation Introduction

Interpretation:

The distance in $\text{km}$ that the vehicle can travel on $20.4\text{ gal}$ of fuel is to be calculated.

Concept introduction:

Heat $\left(q\right)$ is the energy transferred as a consequence of the difference of the temperature between the system and surrounding.

The heat released by the system is negative and the heat taken by the system is positive.

The amount of heat released by the system is equal to the amount of heat absorbed by the surrounding.

The conversion factor to convert $\text{mi/h}$ into $\text{mi/km}$ is:

$\text{1}\text{mi/h}=0.62\text{mi/km}$

(c)

Interpretation Introduction

Interpretation:

If the actual range is $455\text{mi}$ then the answer(b) is to be explained.

Concept introduction:

Heat $\left(q\right)$ is the energy transferred as a consequence of the difference of the temperature between the system and surrounding.

The heat released by the system is negative and the heat taken by the system is positive.

The amount of heat released by the system is equal to the amount of heat absorbed by the surrounding.