66. m by n grid graphs . An m by n grid graph represents a rectangular street grid that is m . blocks by n blocks, as indicated in F i g . 6 - 5 1 . _ F i g u r e 6 - 5 1 a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph. b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph. c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
66. m by n grid graphs . An m by n grid graph represents a rectangular street grid that is m . blocks by n blocks, as indicated in F i g . 6 - 5 1 . _ F i g u r e 6 - 5 1 a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph. b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph. c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
Solution Summary: The author explains that a Hamilton circuit contains all the vertices of the graph exactly once except first and last vertex.
66. m by n grid graphs. An m by n grid graph represents a rectangular street grid that is m. blocks by n blocks, as indicated in
F
i
g
.
6
-
5
1
.
_
F
i
g
u
r
e
6
-
5
1
a. If m and n are both odd, then the m by n grid graph has a Hamilton circuit. Describe the circuit by drawing it on a generic graph.
b. If either m or n is even and the other one is odd, then the m by n grid graph has Hamilton circuit. Describe the circuit by drawing it on a generic graph.
c. . If m and n are both even, then the m by n grid graph does not have a Hamilton circuit. Explain why a Hamilton circuit is impossible.
1 2
21. For the matrix A
=
3 4
find AT (the transpose of A).
22. Determine whether the vector
@
1
3
2
is perpendicular to
-6
3
2
23. If v1
=
(2)
3
and v2 =
compute V1 V2 (dot product).
.
7. Find the eigenvalues of the matrix
(69)
8. Determine whether the vector
(£)
23
is in the span of the vectors
-0-0
and
2
2
1. Solve for x:
2. Simplify:
2x+5=15.
(x+3)² − (x − 2)².
-
b
3. If a = 3 and 6 = 4, find (a + b)² − (a² + b²).
4. Solve for x in 3x² - 12 = 0.
-
Chapter 6 Solutions
Excursions in Mathematics, Loose-Leaf Edition Plus MyLab Math with Pearson eText -- 18 Week Access Card Package
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