Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 6, Problem 6.5P
To determine
The relative compaction in the field.
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1. The results of a standard Proctor test are given in the following table.
a. Determine the maximum dry unit weight of compaction and the optimum moisture content,
given that the Proctor mold volume is 1/30 ft³.
b. Determine the void ratio and the degree of saturation at the optimum moisture content
given G₁= 2.68.
Trial no.
1234567
Weight of moist soil in the mold (lb)
3.92
4.12
4.29
4.37
4.45
4.35
4.20
Moisture content (%)
5.0
7.5
10.0
12.5.
15
17.5
20.0
Chapter 6 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
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- The results of a standard Proctor test are given in the following table. Determine the maximum dry unit weight of compaction and the optimum moisture content. Also determine the moisture content required to achieve 95% of γd(max). Calculate and plot the 80% and 100% saturation lines.arrow_forwardThe results of a standard Proctor test are given in the following table. Given: Mold volume 1/30 ft' and Gs = 2.69. Determine the void ratio and the degree of saturation at the optimum moisture content. Weight of moist soil Moisture in the mold (lb) Trial no. content (%) 1 3.7 8.6 2 4.15 10.6 4.69 12.5 4 4.62 14.9 5 4.02 16.7 6. 3.63 18.3arrow_forward(c) A sample of clay having a mass of 675 gm was coated with paraffin wax. The combined mass of the clay and the wax was found to be 682 gm. The volume was found by immersion in water as 345 ml. The sample was then broken to open. The water content and specific gravity of solids were found to be 15 % and 2.70 respectively. Calculate the bulk density of soil, its void ratio, and degree of saturation. Take specific gravity of wax as 0.89.arrow_forward
- Please answer parts d-farrow_forwardPROBLEM 1 The results of a standard Proctor test are given in the following table. Mass of moist Moisture soil in the mold (kg) Trial Content (%) 1 1.47 10.0 2 1.83 12.5 3 2.02 15 1.95 17.5 5 1.73 20.0 1.69 22.5 After compaction the field unit weight of the soil is determined by means of the sand cone method, the following are the results: O Calibrated dry density of Ottawa sand = 1731 kg/m3 O Mass of Ottawa sand to fill the cone = 0.118 kg O Mass of jar + cone + sand (before use) = 6.08 kg O Mass of jar + cone + sand (after use)= 2.86 kg O Mass of moist soil from the hole = 3.34 kg O Moisture content of moist soil = 12.1% %3D Determine the maximum dry unit weight (kN/m3) of compaction and the optimum moisture content. Given mold volume 943.3 cm3. Note: Check the maximum dry unit weight of compaction and the optimum moisture content using the graphical method and by means of the equation of the line. b. Determine the relative compaction in the field. a.arrow_forwardI need the answer soon as possible, pleasearrow_forward
- Please answer parts a-carrow_forwardA liquid limit test on a clay was performed with the following results. The natural water content of the clay is 38% and plastic limit is 21%. Number of Blows 6 12 20 28 32 Water content (%) 52.5 47.1 42.3 38.6 37.5 What is the liquidity index of this clay? (Use Interpolation) Group of answer choices 0.895 0.96 1.08 0.90 Please answer this asap. For upvote. Thanksarrow_forwardA 627-g sample of sand was found to have the following amounts of material retained on each sieve/pan: 3/8 in. = 22 g, No. 4 = 45 g, No. 8 = 96 g, No. 16 = 122 g, No. 30 = 163 g. No. 50 86 g, No. 100 = 51 g, No. 200 = 30 g, pan = 11 g a. Calculate the fineness modulus of the sand. b. Is this sieve analysis valid for acceptance purposes? Explain why. c. Does the sand meet the particle size criteria of ASTM C 33. Fully justify your answer (list and check all relevant criteria from ASTM C33)arrow_forward
- A hydrometer test was conducted on the material passing sieve No, 200 and the results are listed in the table below, The results of sieve analysis on the soil showed that the percentage passing No. 4 was 90 % and that passing No. 200 was 20 %. Estimate the clay size fraction in the soil. Table : Results of hydrometer test diameter (mm) 0.0700 0.0400 0.0150 0.0020 % finer (combined) 19 finer 95 80 16 65 13 45 0.0010 30 6 Select one:arrow_forward2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture contentarrow_forwardIn a sieve analysis test, 95.5% of the sample is passing the 5mm sieve and 5.13% is passing sieve #200, which of the following is correct about this sample: O There is no clay in the sample ) the percent of silt and clay is: 5.13% There is 4.5% Sand and Gravel in the sample O 95.5% of the sample is Sand and Silt O Oarrow_forward
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