
(a)
Interpretation:
The formation of following solutions should be explained:
500.0 mL of a 5.32 % w/w
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.
The formula for w/w is as follows:
Here,
When solving for the required amount of solute, the following formula is used:

Answer to Problem 6.34P
Explanation of Solution
Given Information:
The concentration is shown as w/w meaning this is mass of solute per mass of solvent.
Since, density of water is 1 g/mL thus, 500 mL of water contains 500 g of water. Substitute known data and solve for mass of solute.
Thus,
(b)
Interpretation:
The formation of following solutions should be explained:
342.0 mL of a 0.443 % w/w benzene solution in toluene.
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.
The formula for w/w is as follows:
Here,
When solving for the required amount of solute, the following formula is used:
(b)

Answer to Problem 6.34P
Explanation of Solution
Given Information:
The concentration is shown as w/w meaning this is mass of solute per mass of solvent.
In this specific case, we do not know which volume or mass each material is, but we do know which one the solvent is, toluene.
Now, get the total volume equation.
Solve simultaneously.
Then, add
(c)
Interpretation:
The formation of following solutions should be explained:
125.5 mL of a 34.2 % w/w dimethyl sulfoxide solution in acetone.
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In mass of solute per unit mass of solvent, or w/w, the total mass of the solute, solvent and solution must be known.
The formula for w/w is as follows:
Here,
When solving for the required amount of solute, the following formula is used:

Answer to Problem 6.34P
Explanation of Solution
Given:
In this specific case, we do not know which volume or mass each material is, but we do know which one is the solvent that is acetone.
Now, get the total volume equation.
Solve simultaneously.
Then, add
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Chapter 6 Solutions
Bundle: Introduction to General, Organic and Biochemistry, 11th + OWLv2, 4 terms (24 months) Printed Access Card
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