Physical Chemistry Plus Mastering Chemistry With Etext -- Access Card Package (3rd Edition) (engel Physical Chemistry Series)
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Chapter 6, Problem 6.33NP

(a)

Interpretation Introduction

Interpretation:

The final pressure and ΔG and ΔA for the process for an isothermal reversible path should be calculated.

Concept Introduction :

For an isothermal process, the change in temperature does not takes place or ΔT=0 .

The change in Gibbs free energy and change in Gibbs Helmholtz energy is represented as follows:

  ΔG=PiPfV.dP

And,

  ΔA=ViVfP.dV

Here,

  ΔG - Gibbs free energy changeΔAGibbs Helmholtz energyV - volumeP - pressure

(b)

Interpretation Introduction

Interpretation:

The reason for ΔG and ΔA to not differ from one another should be explained.

Concept Introduction :

State function is a quantity that has a specific value for a given state. State functions does not depend on the path it takes.

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C 5 4 3 CI 2 the Righ B A 5 4 3 The Lich. OH 10 4 5 3 1 LOOP- -147.52 T 77.17 -45.36 200 190 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 ppm B -126.25 77.03 200 190 180 170 160 150 140 130 120 110 100 90 80 70 60 50 40 30 20 10 ppm 200 190 180 170 160 150 140 130 120 110 100 90 80 TO LL <-50.00 70 60 50 40 30 20 10 ppm 45.06 30.18 -26.45 22.36 --0.00 45.07 7.5 1.93 2.05 -30.24 -22.36 C A 7 8 5 ° 4 3 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 1.0 ppm 9 8 5 4 3 ཡི་ OH 10 2 7.5 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 5 4 3 2 that th 7 I 7.0 6.5 6.0 5.5 5.0 4.5 4.0 3.5 3.0 2.5 2.0 1.5 115 2.21 4.00 1.0 ppm 6.96 2.76 5.01 1.0 ppm 6.30 1.00

Chapter 6 Solutions

Physical Chemistry Plus Mastering Chemistry With Etext -- Access Card Package (3rd Edition) (engel Physical Chemistry Series)

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