
Interpretation:
In each box, when given a formula, the name is to be written and for a given name, the formula is to be written. Refer to nothing but the periodic table printed on your shield.
Formula | Name | Name | Formula |
SeO42-(Se, selenium, Z = 34) |
Gallium sulfate (Gallium, Z = 31) |
||
HCO3- | Perchloric acid | ||
Ne | Lithium | ||
N2O5 | Cobalt(II) chloride hexahydrate |
||
HNO2 | Barium dihydrogen phosphate |
||
CI4 | Hydrosulfuric acid | ||
BaH2 | Magnesium nitride | ||
CaTeO3 (Te, tellurium, Z = 52) |
Selenic acid (Selenium, Z = 34) |
||
HBrO | Calcium sulfite | ||
Fe(NO3)2 | Sodium hydride | ||
MgSO4. 7H2O | Mercury(I) chloride |
Concept introduction:
Most of the chemical compounds exist as a polyatomic ion and the ratio of positive to negative ions present in the substance is expressed as formula of ionic compound. The formula of a chemical compound is given by the lowest whole number ratio of ions in the compound and it is called as a formula unit. Some elements form monoatomic ions having different charges and to differentiate the two ions, size of the charge of ions is included when naming the ion. For group 1A, 2A, 5A-7A elements the charge is not included while naming the ion. In common, the charge is given in the name of an ion only when the ions of an element display more than one charge which is common. In other words, when an ionic compound having a metal that can exist in more than one ionic charge, is named the charge of metal atom should be included in the compound name.

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Chapter 6 Solutions
EBK INTRODUCTORY CHEMISTRY: AN ACTIVE L
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- You may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forward
- Alcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forwardDraw the simplified curved arrow mechanism for the reaction of acetone and CHgLi to give the major product. 4th attempt Π Draw the simplified curved arrow mechanism T 3rd attempt Feedback Ju See Periodic Table See Hint H -H H -I H F See Periodic Table See Hintarrow_forwardSelect the correct reagent to accomplish the first step of this reaction. Then draw a mechanism on the Grignard reagent using curved arrow notation to show how it is converted to the final product. 4th attempt Part 1 (0.5 point) Select the correct reagent to accomplish the first step of this reaction. Choose one: OA Mg in ethanol (EtOH) OB. 2 Li in THF O C. Li in THF D. Mg in THF O E Mg in H2O Part 2 (0.5 point) Br Part 1 Bri Mg CH B CH, 1 Draw intermediate here, but no arrows. © TE See Periodic Table See Hint See Hint ין Harrow_forward
- Select the product for the following reaction. HO HO PCC OH ○ OH O HO ○ HO HO HOarrow_forward5:45 Х Select the final product for the following reaction sequence. O O 1. Mg. ether 2.D.Oarrow_forwardBased on the chart Two similarities between the molecule with alpha glycosidic linkages. Two similarities between the molecules with beta glycosidtic linkages. Two differences between the alpha and beta glycosidic linkages.arrow_forward
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