EBK INTRODUCTION TO HEALTH PHYSICS, FIF
EBK INTRODUCTION TO HEALTH PHYSICS, FIF
5th Edition
ISBN: 9780071835268
Author: Johnson
Publisher: VST
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Chapter 6, Problem 6.27P
To determine

To Calculate:The absorbed dose to the liver.

Expert Solution
Check Mark

Answer to Problem 6.27P

The absorbed dose to the liver is 0.7154rad

Explanation of Solution

Given:

Activity of 99mTc -labeled sulfur colloid is 3mci(111MBq)

The deposited percentage of the injectate is 60%

Formula used:

  D=A˜SA˜=1.44A0TeTe=Tp×TbTp+TbD=1.44A0TeS

Where,

  D - Absorbed dose

  A˜ -The cumulated activity

  A0 - Administered activity

  Te - Effective half-life

  Tp - Physical half-life ( t1/2 - half-life)

  Tb - Biological half-life

  S - Absorbed dose per unit cumulated activity

[Values of S for human phantoms can be found in Medical Internal Radiation Dose (MIRD) pamphlets published by the Society of Nuclear Medicine]

In 99mTc decay,

  S(livertoliver)=4.6×105radμciht1/2(Tp)=6h

Calculation:

  A0=3000μci×0.6=1800μci

Absorb dose to the liver [assuming Tb (there is no biological clearance)],

  D=1.44A0TeSD=1.44×1800μci×6h×4.6×105radμcihD=0.7154rad

Conclusion:

The absorbed dose to the liver = 0.7154rad

To determine

To Calculate:The absorbed dose to the spleen.

Expert Solution
Check Mark

Answer to Problem 6.27P

The absorbed dose to the liver is 2.5661rad

Explanation of Solution

Given:

Activity of 99mTc -labeled sulfur colloid is 3mci(111MBq)

The deposited percentage of the inject is 30% .

Formula used:

  D=A˜SA˜=1.44A0TeTe=Tp×TbTp+TbD=1.44A0TeS

Where,

  D - Absorbed dose

  A˜ -The cumulated activity

  A0 - Administered activity

  Te - Effective half-life

  Tp - Physical half-life ( t1/2 - half-life)

  Tb - Biological half-life

  S - Absorbed dose per unit cumulated activity

[Values of S for human phantoms can be found in Medical Internal Radiation Dose (MIRD) pamphlets published by the Society of Nuclear Medicine]

In 99mTc decay,

  S(spleentospleen)=3.3×104radμciht1/2(Tp)=6h

Calculation:

  A0=3000μci×0.3=900μci

Absorb dose to the spleen [assuming Tb (there is no biological clearance)],

  D=1.44A0TeSD=1.44×900μci×6h×3.3×104radμcihD=2.5661rad

Conclusion:

The absorbed dose to the spleen = 2.5661rad

To determine

To Calculate:The absorbed dose to the red marrow.

Expert Solution
Check Mark

Answer to Problem 6.27P

The absorbed dose to the red marrow is 0.0804rad

Explanation of Solution

Given:

Activity of 99mTc -labeled sulfur colloid is 3mci(111MBq)

The deposited percentage of the inject is 10% .

Formula used:

  D=A˜SA˜=1.44A0TeTe=Tp×TbTp+TbD=1.44A0TeS

Where,

  D - Absorbed dose

  A˜ -The cumulated activity

  A0 - Administered activity

  Te - Effective half-life

  Tp - Physical half-life ( t1/2 - half-life)

  Tb - Biological half-life

  S - Absorbed dose per unit cumulated activity

[Values of S for human phantoms can be found in Medical Internal Radiation Dose (MIRD) pamphlets published by the Society of Nuclear Medicine]

In 99mTc decay,

  S(redmarrowtoredmarrow)=3.1×105radμciht1/2(Tp)=6h

Calculation:

  A0=3000μci×0.1=300μci

Absorb dose to the red marrow [assuming Tb (there is no biological clearance)],

  D=1.44A0TeSD=1.44×300μci×6h×3.1×105radμcihD=0.0804rad

Conclusion:

The absorbed dose to the red marrow = 0.0804rad

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