The Basic Practice of Statistics
The Basic Practice of Statistics
8th Edition
ISBN: 9781319042578
Author: David S. Moore, William I. Notz, Michael A. Fligner
Publisher: W. H. Freeman
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 6, Problem 6.26E
To determine

The two-way table for the given situation may vary. One of the possible answers is given below:

To give: The two-way for the given situation.

To show: The obese smokers and obese non-smokers who are more likely to die earlier than people who are not obese.

To check: Whether the Simpson’s paradox holds good for the given situation.

Expert Solution & Answer
Check Mark

Answer to Problem 6.26E

The two-way table for smokers is given below:

Obese
Death Yes No
Yes 8 57
No 192 1,443
Total 200 1,500

The two-way table for non-smokers is given below:

Obese
Death Yes No
Yes 8 6
No 592 594
Total 600 600

The result tells that 4% of obese smokers had died, 1.3% of obese non-smokers had died. However, only 3.8% of not obese smokers had died and 1% of not obese non-smokers had died.

The Simpson’s paradox holds good for the given situation because the two individual tables tell that obese people are more prone to death but the combined table tells that non-obese people who are smoking are more prone to death.

Explanation of Solution

Given info:

Two-way table can be constructed using obese (yes or no) and death (yes or no) for smokers and non-smokers. Also, combine the two-way table of smokers and non-smokers with respect to obese and death.

Calculation:

The two-way table for smokers is constructed by taking death as a row variable and obese as a column variable.

The two-way table for smokers is given below:

Table 1

Obese
Death Yes No
Yes 8 57
No 192 1,443
Total 200 1,500

The two-way table for non-smokers is given below:

Table 2

Obese
Death Yes No
Yes 8 6
No 592 594
Total 600 600

Percentage of obese smokers who died is given below:

(Percentage ofobese smokerswho were died)=Number of people who are obese given that died earlyTotal number of people who are obese=8200×100=0.04×100=4

Thus, 4% of obese smokers had died.

Percentage of obese nonsmokers who died is given below:

(Percentage ofobese nonsmokerswho were died)=Number of people who are obese given that died earlyTotal number of people who are obese=8600×100=0.013×100=1.3

Thus, 1.3% of obese non-smokers had died.

Percentage of not obese smokers who died is given below:

(Percentage ofnonobese smokerswho were died)=Number of people who are not obese given that died earlyTotal number of people who are not obese=571,500×100=0.038×100=3.8

Thus, 3.8% of not obese smokers had died.

Percentage of non-smokers who are not obese died is given below:

(Percentage ofnot obese nonsmokerswho were died)=Number of people who are not obese given that died earlyTotal number of people who are not obese=6600×100=0.01×100=1

Thus, 1% of not obese non-smokers had died.

Combined table:

The combined table is obtained by combining the corresponding values from Table 1 and Table 2.

Table 3

Obese
Death Yes No
Yes 16 63
No 784 2,037
Total 800 2,100

Percentage of non-obese smokers who died is given below:

(Percentage of non-obese smokerswho have died)=Number of people who are not obese but diedTotal number of people who are not obese=632,100×100=0.03×100=3

Thus, 3% of non-obese smokers had died.

Percentage of obese smokers who died is given below:

(Percentage of obese smokerswho have died)=Number of people who are obese also diedTotal number of people who are obese=16800×100=0.02×100=2

Thus, 2% of obese smokers had died.

The percentage of deaths for smokers is given below:

Obese
Death Yes No
Yes 4% 3.8%

The percentage of deaths for non-smokers is given below:

Obese
Death Yes No
Yes 1.3% 1%

The percentage of deaths under combined table is given below:

Obese
Death Yes No
Yes 2% 3%

Justification:

Simpson paradox:

Conclusion drawn from aggregated table might go wrong by drawing conclusions from the individual tables.

Thus, the scenario of Simpson’s paradox is stated. The individual tables tell that obese people are more prone to death, but the combined table tells that non-obese people who are smoking are more prone to death.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Two measurements are made of some quantity. For the first measurement, the average is 74.4528, the RMS error is 6.7441, and the uncertainty of the mean is 0.9264. For the second one, the average is 76.8415, the standard deviation is 8.3348, and the uncertainty of the mean is 1.1448. The expected value is exactly 75. 13. Express the first measurement in public notation. 14. Is there a significant difference between the two measurements? 1 15. How does the first measurement compare with the expected value? 16. How does the second measurement compare with the expected value?
A hat contains slips of paper numbered 1 through 6. You draw two slips of paper at random from the hat,without replacing the first slip into the hat.(a) (5 points) Write out the sample space S for this experiment.(b) (5 points) Express the event E : {the sum of the numbers on the slips of paper is 4} as a subset of S.(c) (5 points) Find P(E)(d) (5 points) Let F = {the larger minus the smaller number is 0}. What is P(F )?(e) (5 points) Are E and F disjoint? Why or why not?(f) (5 points) Find P(E ∪ F )
In addition to the in-school milk supplement program, the nurse would like to increase the use of daily vitamin supplements for the children by visiting homes and educating about the merits of vitamins. She believes that currently, about 50% of families with school-age children give the children a daily megavitamin. She would like to increase this to 70%. She plans a two-group study, where one group serves as a control and the other group receives her visits. How many families should she expect to visit to have 80% power of detecting this difference? Assume that drop-out rate is 5%.
Knowledge Booster
Background pattern image
Statistics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
MATLAB: An Introduction with Applications
Statistics
ISBN:9781119256830
Author:Amos Gilat
Publisher:John Wiley & Sons Inc
Text book image
Probability and Statistics for Engineering and th...
Statistics
ISBN:9781305251809
Author:Jay L. Devore
Publisher:Cengage Learning
Text book image
Statistics for The Behavioral Sciences (MindTap C...
Statistics
ISBN:9781305504912
Author:Frederick J Gravetter, Larry B. Wallnau
Publisher:Cengage Learning
Text book image
Elementary Statistics: Picturing the World (7th E...
Statistics
ISBN:9780134683416
Author:Ron Larson, Betsy Farber
Publisher:PEARSON
Text book image
The Basic Practice of Statistics
Statistics
ISBN:9781319042578
Author:David S. Moore, William I. Notz, Michael A. Fligner
Publisher:W. H. Freeman
Text book image
Introduction to the Practice of Statistics
Statistics
ISBN:9781319013387
Author:David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:W. H. Freeman
The Shape of Data: Distributions: Crash Course Statistics #7; Author: CrashCourse;https://www.youtube.com/watch?v=bPFNxD3Yg6U;License: Standard YouTube License, CC-BY
Shape, Center, and Spread - Module 20.2 (Part 1); Author: Mrmathblog;https://www.youtube.com/watch?v=COaid7O_Gag;License: Standard YouTube License, CC-BY
Shape, Center and Spread; Author: Emily Murdock;https://www.youtube.com/watch?v=_YyW0DSCzpM;License: Standard Youtube License